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Using Eccentricity Find an equation of the ellipse with vertices \((0, \pm 8)\) and eccentricity \(e=\frac{1}{2}\)

Short Answer

Expert verified
The equation of the ellipse with vertices at \((0, \pm 8)\) and eccentricity \(e = \frac{1}{2}\) is \(\frac{x^2}{64} + \frac{y^2}{48} = 1\).

Step by step solution

01

Identify known values

The given values are the vertices located at \((0, \pm 8)\) and the eccentricity \(e = \frac{1}{2}\). These indicate that the value of \(a\) is 8 (as the vertices are on the y-axis) and \(e = \frac{1}{2}\).
02

Find the value of \(b\)

To find the value of \(b\), plug these known values in the eccentricity equation\[e = \sqrt{1 - \frac{b^2}{a^2}}\]After rearranging the equation and substituting \(e\) and \(a\), we get\[\frac{1}{2} = \sqrt{1 - \frac{b^2}{64}}\]Square both sides of the equation, we have\[\frac{1}{4} = 1 - \frac{b^2}{64}\]Reorganize to solve for \(b^2\), we get\[b^2 = 64(1 - \frac{1}{4}) = 48\].
03

Derive the equation of the ellipse

Now that we have \(a = 8\) and \(b = \sqrt{48}\), we apply these values into the ellipse equation\[\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\]This simplifies to\[\frac{x^2}{64} + \frac{y^2}{48} = 1\]This is the equation of the ellipse.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eccentricity
Eccentricity is a concept that measures how much an ellipse deviates from being a circle. It is denoted by the letter "e" and is a critical parameter in defining the shape of an ellipse.

In mathematical terms, eccentricity is defined as the ratio of the distance between the foci of the ellipse and the length of the major axis. For an ellipse, this value always lies between 0 and 1. When eccentricity is zero, the ellipse is a perfect circle. In the case of a given problem, the eccentricity is provided as \(e=\frac{1}{2}\).

This implies that the ellipse is neither a perfect circle nor too stretched. The standard equation for eccentricity when dealing with ellipses aligned with the Cartesian coordinate system is:\[ e = \sqrt{1 - \frac{b^2}{a^2}} \]

By rearranging this equation, we can derive any unknown component if all other elements are known. Here, with \(e=\frac{1}{2}\) and the vertex \(a=8\), we use it to find the value of \(b\), helping us form the complete image of the ellipse.
Vertices
Vertices are crucial in defining the dimensions of an ellipse. They mark the endpoints of the major axis, the longest diameter of the ellipse. In our problem context, the vertices are given as \((0, \pm 8)\), indicating they lie on the y-axis.

The presence and positions of vertices primarily infer:
  • Which axis is the major axis (here it is the y-axis, because the coordinates vary along y while remaining fixed at x = 0).
  • The value of \(a\) which is the semi-major axis. Given as 8 since the vertices are at 8 units on both sides of the center at (0,0).
These vertices help determine other parameters such as focal distances, which are derived by knowing \(a\), \(b\), and the center's position, all of which aid in writing the ellipse's equation. Understanding vertices and their significance helps guide towards the complete geometric and algebraic understanding of an ellipse.
Ellipse
An ellipse is a geometric shape that resembles a stretched circle. It encompasses two axes: the major axis and the minor axis. The core idea is that every point on an ellipse is at equal combined distances from two fixed points called foci.

For an ellipse centered at the origin in the Cartesian plane, the equation is given by:
\[\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\]
The roles of \(a\) and \(b\) are dependent on which axis is the major one:
  • \(a\) represents the semi-major axis.
  • \(b\) represents the semi-minor axis.
In the provided problem, by identifying the vertices along the y-axis, it is evident that it is the major axis and hence \(a=8\). Using the eccentricity to solve for \(b\), the minor axis, we can complete the ellipse equation: \(\frac{x^2}{64} + \frac{y^2}{48} = 1\).

Understanding the placement and calculation of quantities like eccentrics, axes, and foci within the equation not only solves mathematical problems but enriches the conceptual insight into how ellipses naturally form and relate to each other.

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Most popular questions from this chapter

A projectile is launched at a height of \(h\) feet above the ground at an angle of \(\theta\) with the horizontal. The initial velocity is \(v_{0}\) feet per second, and the path of the projectile is modeled by the parametric equations $$x=\left(v_{0} \cos \theta\right) t$$ and $$y=h+\left(v_{0} \sin \theta\right) t-16 t^{2}.$$ Use a graphing utility to graph the paths of a projectile launched from ground level at each value of \(\boldsymbol{\theta}\) and \(v_{0} .\) For each case, use the graph to approximate the maximum height and the range of the projectile. (a) \(\theta=15^{\circ}, \quad v_{0}=50\) feet per second (b) \(\theta=15^{\circ}, \quad v_{0}=120\) feet per second (c) \(\theta=10^{\circ}, \quad v_{0}=50\) feet per second (d) \(\theta=10^{\circ}, \quad v_{0}=120\) feet per second

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