Chapter 6: Problem 38
Use a graphing utility to graph the curve represented by the parametric equations. $$\begin{aligned} &x=t+1\\\ &y=\sqrt{2-t} \end{aligned}$$
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Chapter 6: Problem 38
Use a graphing utility to graph the curve represented by the parametric equations. $$\begin{aligned} &x=t+1\\\ &y=\sqrt{2-t} \end{aligned}$$
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Determine whether the statement is true or false. Justify your answer. If the vertex and focus of a parabola are on a horizontal line, then the directrix of the parabola is vertical.
The points represent the vertices of a triangle. (a) Draw triangle \(A B C\) in the coordinate plane, (b) find the altitude from vertex \(B\) of the triangle to side \(A C,\) and \((\mathrm{c})\) find the area of the triangle. $$A(-1,0), B(0,3), C(3,1)$$
The graph of the parametric equations \(x=t\) and \(y=t^{2}\) is shown below. Determine whether the graph would change for each set of parametric equations. If so, how would it change? (GRAPH CANNOT COPY) (a) \(x=-t, y=t^{2}\) (b) \(x=t+1, y=t^{2}\) (c) \(x=t, y=t^{2}+1\)
In Exercises \(91-116\), convert the polar equation to rectangular form. $$r=\frac{5}{1-4 \cos \theta}$$
Determine whether the statement is true or false. Justify your answer. It is possible for a parabola to intersect its directrix.
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