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A Graphing a Rotated Conic, use a graphing utility to graph the rotated conic. $$r=\frac{6}{2+\sin (\theta+\pi / 6)}$$

Short Answer

Expert verified
To solve the exercise, there should be a solid understanding of the polar coordinate system, knowledge on how to accommodate the angle rotation into the function, and lastly graphing it correctly using a graphing utility.

Step by step solution

01

Understanding Polar Coordinates

In polar coordinates, each point on the plane is determined by a distance from a reference point, or the origin, and an angle from a reference direction. The angle, \( \theta \), is measured counterclockwise from the x-axis (the polar axis). In this exercise, we have to graph the conic using the given polar equation \(r=\frac{6}{2+\sin (\theta+\pi / 6)}\), where \( r \) is the distance from origin to the point on the conic and \( \theta \) is the angle made by line joining origin and point with the x-axis.
02

Understanding Rotation

Here, the rotation of the conic is given by \(\pi / 6\) radians, which indicates that the conic is rotated by that angle. To account for this in our equation, we adjust the angle \(\theta\) in the function. In the given equation, \(\theta\) is being summed with this rotation, therefore, points on the conic are going to be shifted by \(\pi/6\) radians counterclockwise.
03

Graphing the Rotated Conic

To graph the rotated conic, one should use a graphing tool. Ideally, an online graphing calculator can be used. One should input the equation into the tool correctly, replacing \(r\) and \(\theta\) where necessary, taking into consideration any constants such as the \(\pi/6\) rotation. This should yield a visual representation of the rotating conic as specified in the exercise.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
Polar coordinates offer a way of describing the location of points in a plane using a radius and an angle, as opposed to the x and y values used in Cartesian coordinates. Every point in polar coordinates is expressed as \( (r, \theta) \) where \( r \) is the distance from the origin (also known as the pole) to the point, and \( \theta \) is the angle measured in radians from the positive x-axis (the polar axis) to the line segment connecting the origin to the point.

This system is particularly helpful when dealing with curves that are circular or spiral in nature. For example, a circle centered at the origin with radius \( a \) would have a simple polar equation of \( r = a \) compared to its more complex Cartesian equation. The polar approach can simplify both the equation and the graphing of shapes that have symmetry around a point - like conic sections.
Polar Equations
Polar equations represent curves by expressing the radius as a function of the angle \( \theta \). The equation \( r = f(\theta) \) embodies the relationship between the radius and the angle, and it can give rise to a variety of shapes depending on its form. For instance, a polar equation can describe a circle, a spiral, or even more complex forms like cardioids or rose curves.

The polar equation given in our exercise, \( r=\frac{6}{2+\sin (\theta+\pi / 6)} \) is designed in a way that the denominator changes as the angle changes, which in turn alters the radius. As \( \theta \) increases, the sine function oscillates, thus making the radius \( r \) vary in a manner that outlines a conic section. Understanding how this function behaves is key to visualizing the curve before even graphing it.
Graphing Utility
A graphing utility, such as an online calculator or specialized software, is a valuable tool for visualizing complex equations and shapes, especially when dealing with polar coordinates and rotated conics. These utilities can accurately plot points and generate curves that might be challenging to draw by hand.

To use a graphing utility, you input the polar equation and specify the range for \( \theta \) you want to observe. The utility handles the tedious calculations and displays the curve. This helps to quickly understand how the radius changes with the angle, especially in a rotated conic where the relationship is not immediately intuitive. Some graphing utilities even provide options for animating the rotation, offering deeper insights into the geometry at play.
Conic Section Rotation
Rotating a conic section involves turning it about the origin to a certain angle. When we say a conic is rotated by \( \pi / 6 \) radians, as in our exercise, this implies that every point on the conic has been shifted around the pole, without changing their relative distances. A non-rotated conic has its major and minor axes aligned with the Cartesian axes, but a rotated one does not.

Adding a rotation to the angle \( \theta \) in the polar equation (\( \theta+\pi / 6 \) in our case) achieves this effect mathematically. The result is that the graph of the conic will be tilted, which could change how the conic intersects the axes or, if it is an ellipse, the orientation of its major and minor axes. The key to understanding a rotated conic is to visualize or graph the shape before rotation and then apply the rotation to see the new orientation.

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Most popular questions from this chapter

A circle and a parabola can have \(0,1,2,3,\) or 4 points of intersection. Sketch the circle \(x^{2}+y^{2}=4 .\) Discuss how this circle could intersect a parabola with an equation of the form \(y=x^{2}+C .\) Then find the values of \(C\) for each of the five cases described below. Use a graphing utility to verify your results. (a) No points of intersection (b) One point of intersection (c) Two points of intersection (d) Three points of intersection (e) Four points of intersection

An archer releases an arrow from a bow at a point 5 feet above the ground. The arrow leaves the bow at an angle of \(15^{\circ}\) with the horizontal and at an initial speed of 225 feet per second. (a) Write a set of parametric equations that model the path of the arrow. (See Exercises 93 and 94 .) (b) Assuming the ground is level, find the distance the arrow travels before it hits the ground. (Ignore air resistance.) (c) Use a graphing utility to graph the path of the arrow and approximate its maximum height. (d) Find the total time the arrow is in the air.

A projectile is launched at a height of \(h\) feet above the ground at an angle of \(\theta\) with the horizontal. The initial velocity is \(v_{0}\) feet per second, and the path of the projectile is modeled by the parametric equations $$x=\left(v_{0} \cos \theta\right) t$$ and $$y=h+\left(v_{0} \sin \theta\right) t-16 t^{2}.$$ Use a graphing utility to graph the paths of a projectile launched from ground level at each value of \(\boldsymbol{\theta}\) and \(v_{0} .\) For each case, use the graph to approximate the maximum height and the range of the projectile. (a) \(\theta=15^{\circ}, \quad v_{0}=50\) feet per second (b) \(\theta=15^{\circ}, \quad v_{0}=120\) feet per second (c) \(\theta=10^{\circ}, \quad v_{0}=50\) feet per second (d) \(\theta=10^{\circ}, \quad v_{0}=120\) feet per second

Determine whether the statement is true or false. Justify your answer. To find the angle between two lines whose angles of inclination \(\theta_{1}\) and \(\theta_{2}\) are known, substitute \(\theta_{1}\) and \(\theta_{2}\) for \(m_{1}\) and \(m_{2},\) respectively, in the formula for the angle between two lines.

Find the distance between the point and the line. Point \((1,1)\) Line \(y=x+1\)

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