Chapter 6: Problem 1
The locus of a point in the plane that moves such that its distance from a fixed point (focus) is in a constant ratio to its distance from a fixed line (directrix) is a _____.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 6: Problem 1
The locus of a point in the plane that moves such that its distance from a fixed point (focus) is in a constant ratio to its distance from a fixed line (directrix) is a _____.
All the tools & learning materials you need for study success - in one app.
Get started for free
Find the distance between the point and the line. Point \((1,1)\) Line \(y=x+1\)
In Exercises \(71-90,\) convert the rectangular equation to polar form. Assume \(a > 0\). $$\left(x^{2}+y^{2}\right)^{2}=9\left(x^{2}-y^{2}\right)$$
Explain how the graph of each conic differs from the graph of \(\left.r=\frac{5}{1+\sin \theta} . \text { (See Exercise } 17 .\right)\) (a) \(r=\frac{5}{1-\cos \theta}\) (b) \(r=\frac{5}{1-\sin \theta}\) (c) \(r=\frac{5}{1+\cos \theta}\) (d) \(r=\frac{5}{1-\sin [\theta-(\pi / 4)]}\)
Determine whether the statement is true or false. Justify your answer. A line that has an inclination greater than \(\pi / 2\) radians has a negative slope.
In Exercises \(117-126\), convert the polar equation to rectangular form. Then sketch its graph. $$r=6$$
What do you think about this solution?
We value your feedback to improve our textbook solutions.