/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Solve the multiple-angle equatio... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve the multiple-angle equation. $$2 \cos \frac{x}{2}-\sqrt{2}=0$$

Short Answer

Expert verified
x = \(\frac{\pi}{2}\) + 4\(\pi\)k, x = -\(\frac{3\pi}{2}\) + 4\(\pi\)k

Step by step solution

01

Isolate the cosine term

First, isolate the cos term on one side. This can be done by adding \(\sqrt{2}\) on both sides: 2 cos(\(\frac{x}{2}\)) - \(\sqrt{2}\) + \(\sqrt{2}\) = 0 + \(\sqrt{2}\)Which simplifies to: 2 cos(\(\frac{x}{2}\)) = \(\sqrt{2}\)
02

Solve for the angle \(\frac{x}{2}\)

Now, to solve for the angle \(\frac{x}{2}\), divide both sides by 2: cos(\(\frac{x}{2}\)) = \(\frac{\sqrt{2}}{2}\) Now, refer to the unit circle where cosine \(\frac{\sqrt{2}}{2}\) lies. It is related to the angle \(\frac{\pi}{4}\), and \(-\frac{3\pi}{4}\) as cosine is positive in both first and fourth quadrants: \(\frac{x}{2}\) = \(\frac{\pi}{4}\) + 2\(\pi\)k or \(\frac{x}{2}\) = -\(\frac{3\pi}{4}\) + 2\(\pi\)k where k is any integer.
03

Solve for x

Finally solve for x by multiplying the equation through by 2: x = 2(\(\frac{\pi}{4}\) + 2\(\pi\)k) or x = 2(-\(\frac{3\pi}{4}\) + 2\(\pi\)k)This simplifies to: x = \(\frac{\pi}{2}\) + 4\(\pi\)k and x = -\(\frac{3\pi}{2}\) + 4\(\pi\)k.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.