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Solve the multiple-angle equation. $$2 \cos 2 x-1=0$$

Short Answer

Expert verified
The solutions for x that satisfy the equation \(2 \cos 2x -1 = 0\) are \(x = 30^\circ, 150^\circ, -30^\circ, -150^\circ \).

Step by step solution

01

Interpret the Function

First, recognize that the problem is a trigonometric equation and involves cosine. The initial form, \(2 \cos 2x -1\), needs to be rearranged so the equation \(2 \cos 2x -1 = 0\) can be solved for \(x\).
02

Solve for Cosine

Add 1 to both sides to isolate the \(\cos 2x\) on one side of the equation. The equation becomes \(2 \cos 2x = 1\). Divide both sides by 2 to solve for \(\cos 2x\). Hence, \(\cos 2x = 0.5\).
03

Solve double-angle equation

Since the equation is in the format of a double angle, it needs to be solved accordingly. When cosine equals 0.5, the standard angles on the unit circle are \(60^\circ\) and \(300^\circ\). Therefore, \(2x = 60^\circ\) or \(2x = 300^\circ\). Remember, for cosine, we also have to consider angles on the negative side as the cosine function is positive in the first and fourth quadrants. As a result, \(2x = -60^\circ\) or \(2x = -300^\circ\). Thus, the solution to the double-angle equation is \(x = 30^\circ, 150^\circ, -30^\circ, -150^\circ \).

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