/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 Factor the trigonometric express... [FREE SOLUTION] | 91Ó°ÊÓ

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Factor the trigonometric expression. There is more than one correct form of each answer. $$6 \cos ^{2} x+5 \cos x-6$$

Short Answer

Expert verified
The factorized form of the given trigonometric expression is \((\cos x+1)(\cos x-1/2)\).

Step by step solution

01

Identify the quadratic form of the given expression

The given expression is \(6 \cos ^{2} x+5 \cos x-6\), we note that it is in quadratic form which is \(ax^2+bx+c\). Here, \(\cos x\) is 'x' and a=6, b=5, and c=-6.
02

Factorize the quadratic

The expression is now seen as a standard quadratic, recall that a quadratic \(ax^2+bx+c\) can be expressed as \((x-p)(x-q)\) where 'p' and 'q' are roots of the equation \(ax^2+bx+c = 0\). Solving \(6x^2+5x-6=0\) gives x=-1 and x=1/2. Therefore, our quadratic can be factored as \((x+1)(x-1/2)\)
03

Replace 'x' with \(\cos x\)

Substitute \(\cos x\) in place of x in the solution obtained in step 2, we get: \((\cos x+1)(\cos x-1/2)\).

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