/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 Sketch the graph of the function... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sketch the graph of the function. (Include two full periods.) $$y=\sin \left(x-\frac{\pi}{2}\right)$$

Short Answer

Expert verified
The graph of the function \(y=\sin(x-\frac{\pi}{2})\) represents a rightward shift of the sine function by \(\frac{\pi}{2}\) units, oscillating between -1 and 1 and maintaining a period of \(2\pi\).

Step by step solution

01

Understanding the base function

Begin by recalling the standard sine function \(y=\sin x\), which has a period of \(2\pi\) and which oscillates between -1 and 1.
02

Understanding the transformation

The function \(y=\sin \left(x-\frac{\pi}{2}\right)\) is a horizontal shift of the standard sine function. It is shifted \(\frac{\pi}{2}\) units to right. This does not affect the period or the amplitude of the function.
03

Plotting the function

Now, to sketch two full periods of the function \(\sin(x - \frac{\pi}{2})\), it can be helpful to first plot the sine function \(y=\sin x\), then shift all points to the right by \(\frac{\pi}{2}\). Start at the point (0, 0), but remember to shift to the right by \(\frac{\pi}{2}\), so the first point becomes \((\frac{\pi}{2}, 0)\). Follow this procedure by marking equivalent points of the sine curve, and shift them by \(\frac{\pi}{2}\). Ensure to complete two full periods.

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