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Use trigonometric identities to transform the left side of the equation into the right side \((0<\theta<\pi 2)\). $$\tan \theta \cot \theta=1$$

Short Answer

Expert verified
By leveraging the trigonometric identities for \(\tan \theta\) and \(\cot \theta\), and simplifying our transformed equation, we can successfully show that \(\tan \theta \cot \theta = 1\).

Step by step solution

01

Transform the Left Side of the Equation

Begin by replacing the \(\tan \theta\) and \(\cot \theta\) in the left side of the equation with their respective identities. So, \(\tan \theta \cot \theta\) will become \((\sin \theta / \cos \theta) * (\cos \theta / \sin \theta)\)
02

Simplify the Expression

Now, simplify the equation by cancelling out the similar terms. Here, we can see that \(\sin \theta\) and \(\cos \theta\) appear in both the numerator and the denominator, therefore they can be cancelled out which will give you '1'.
03

Compare the Result with the Right Side of the Equation

Finally, compare the result from step 2 with the right side of the equation. Since '1' equals '1', this verifies that the mathematical transformation was done correctly.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transformation of Equations
The concept of transforming equations is often seen in algebra and trigonometry. Essentially, it involves rewriting one or both sides of an equation to reveal their equivalence through various transformations and substitutions. In this exercise, we aimed to transform the left side of the equation so that it matches the right side, which is simply the number 1.The first step is identifying which trigonometric identities can be applied. Trigonometric identities are known relationships involving trigonometric functions that can be substituted into the equation. By substituting \( \tan \theta \) with \( \frac{\sin \theta}{\cos \theta} \) and \( \cot \theta \)with\( \frac{\cos \theta}{\sin \theta} \), we transform the left side into a form that is more manageable for simplification. This approach is crucial for revealing the hidden equivalencies in complex equations.
Trigonometric Simplification
Trigonometric simplification is a key skill when manipulating trigonometric functions within an equation. In this instance, we simplified \( \tan \theta \cot \theta \) by utilizing the fundamental identities of tangent and cotangent. The expression was initially transformed to\( (\frac{\sin \theta}{\cos \theta}) \times (\frac{\cos \theta}{\sin \theta}) \).This step alone highlights the power of trigonometric identities, which reveal direct equivalent expressions that can simplify numerous problems.Simplification involved eliminating common terms that appear in both the numerator and the denominator:
  • In this case, \( \sin \theta \) in the numerator and denominator cancel each other out.
  • Likewise, \( \cos \theta \) from both the numerator and the denominator cancel.
The result is a simplified expression, which is the number 1, aligning perfectly with the right side of the original equation. This kind of simplification is crucial for verifying the equivalence of trigonometric expressions.
Angle Identities
Angle identities, also known as trigonometric identities, are vital for connecting various trigonometric functions. These identities include basic ratios involving sine, cosine, tangent, and their reciprocals: cosecant, secant, and cotangent. In our problem, utilizing the relationships \( \tan \theta = \frac{\sin \theta}{\cos \theta} \) and \( \cot \theta = \frac{\cos \theta}{\sin \theta} \) played a pivotal role in the transformation and simplification of the equation.These fundamental identities are the backbone of trigonometric transformations and can often simplify problems into straightforward expressions.
  • They can help convert products or powers into simpler forms.
  • They provide the means to express complex trigonometric expressions in terms of basic ratios.
Thus, understanding and mastering these angle identities not only aids in solving equations but also equips students with the tools for analyzing complex trigonometric relationships. This understanding enhances problem-solving efficiency and mathematical intuition.

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Most popular questions from this chapter

Angular and Linear Speeds A DVD is approximately 12 centimeters in diameter. The drive motor of the DVD player rotates between 200 and 500 revolutions per minute, depending on what track is being read. (a) Find an interval for the angular speed of the DVD as it rotates. (b) Find an interval for the linear speed of a point on the outermost track as the DVD rotates.

Consider the function \(f(x)=x-\cos x\) (a) Use a graphing utility to graph the function and verify that there exists a zero between 0 and \(1 .\) Use the graph to approximate the zero. (b) Starting with \(x_{0}=1,\) generate a sequence \(x_{1}, x_{2}\) \(x_{3}, \ldots,\) where \(x_{n}=\cos \left(x_{n-1}\right) .\) For example \(x_{0}=1\) \(x_{1}=\cos \left(x_{0}\right)\) \(x_{2}=\cos \left(x_{1}\right)\) \(x_{3}=\cos \left(x_{2}\right)\) What value does the sequence approach?

For the simple harmonic motion described by the trigonometric function, find (a) the maximum displacement, (b) the frequency, (c) the value of \(d\) when \(t=5,\) and (d) the least positive value of \(t\) for which \(d=0 .\) Use a graphing utility to verify your results. $$d=\frac{1}{64} \sin 792 \pi t$$

Sketch a graph of the function and compare the graph of \(g\) with the graph of \(f(x)=\arcsin x\). $$g(x)=\arcsin (x-1)$$

The normal monthly high temperatures \(H\) (in degrees Fahrenheit) in Erie, Pennsylvania, are approximated by $$H(t)=56.94-20.86 \cos \left(\frac{\pi t}{6}\right)-11.58 \sin \left(\frac{\pi t}{6}\right)$$ and the normal monthly low temperatures \(L\) are approximated by $$L(t)=41.80-17.13 \cos \left(\frac{\pi t}{6}\right)-13.39 \sin \left(\frac{\pi t}{6}\right)$$ where \(t\) is the time (in months), with \(t=1\) corresponding to January (see figure). (Source: National Climatic Data Center (GRAPH CANNOT COPY). (a) What is the period of each function? (b) During what part of the year is the difference between the normal high and normal low temperatures greatest? When is it smallest? (c) The sun is northernmost in the sky around June \(21,\) but the graph shows the warmest temperatures at a later date. Approximate the lag time of the temperatures relative to the position of the sun.

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