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Describe the relationship between the graphs of \(f\) and \(g .\) Consider amplitude, period, and shifts. $$\begin{aligned} &f(x)=\sin x\\\ &g(x)=\sin 3 x \end{aligned}$$

Short Answer

Expert verified
The amplitude of both functions is 1. However, while the period of \( f(x) = \sin x \) is \( 2\pi \), \( g(x) = \sin 3x \) has a period of \( \frac{2\pi}{3} \). There are no phase shifts in either function.

Step by step solution

01

Amplitude Comparison

The amplitude of a function is its peak positive or negative value. For both \( f(x) \) and \( g(x) \), the amplitude is 1 as, regardless of the coefficient of \( x \) in sin functions, the output will always vary from -1 to 1.
02

Period Comparison

The period of a function is the interval over which its shape repeats. For \( f(x) = \sin x \), the period is \( 2\pi \), as this is the interval over which the sine function typically repeats. When we switch to \( g(x) = \sin 3x \), however, the period changes. The coefficient in front of \( x \) in the sine function acts as frequency multiplier: the period becomes \( \frac{2\pi}{3} \), three times faster than the period of \( f(x) \).
03

Phase Shift Comparison

The phase shift of a function is a horizontal shift. For both \( f(x) = \sin x \) and \( g(x) = \sin 3x \), there are no horizontal or vertical shifts since there are no additional constants modifying the functions.

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