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Find the period and amplitude. $$y=3 \sin 10 x$$

Short Answer

Expert verified
The amplitude of the function \(y=3 \sin 10x\) is \(3\) and the period is \(\frac{\pi}{5}\).

Step by step solution

01

Identify the Amplitude

In this case, the amplitude is represented by the coefficient of the sine function, which is \(3\). This means that it is the maximum distance from the centreline (or the mean) of the wave on the y-axis. So, the amplitude of the function is \(3\).
02

Find the Period

Period of a function is calculated as \( \frac{2\pi}{|b|}\), where \(b\) is the frequency of the sine function. Here, \(b = 10\), so the period is calculated as \( \frac{2\pi}{10} = \frac{\pi}{5}\).

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