/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 75 Solve the equation algebraically... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the equation algebraically. Round your result to three decimal places. Verify your answer using a graphing utility. $$-x e^{-x}+e^{-x}=0$$

Short Answer

Expert verified
The solution to the equation is \(x = 1\).

Step by step solution

01

Simplify the Equation

Looking at the equation \(-x e^{-x}+e^{-x}=0\), we notice that the term \(e^{-x}\) can be factored out, leading to the more simplified form of \((1-x)e^{-x}=0\).
02

Solve the Equation

Now we have two expressions separated by a multiplication sign. For their multiplication to be zero, at least one of them must be zero. Thus, we set each expression equal to zero and solve for x. Setting \(1-x=0\) leads to \(x=1\). The term \(e^{-x}=0\) cannot be solved since exponential function will never be equal to zero.
03

Verification

To verify the solution, graph the original function \(-x e^{-x}+e^{-x}\) and check if the graph crosses the x-axis at \(x=1\). If it does, then the solution is correct. Verifying the solution using a graphing tool, we see that our solution \(x=1\) is valid.

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