/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 Find the exponential model that ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the exponential model that fits the points shown in the graph or table. $$\begin{array}{|c|c|c|} \hline x & 0 & 4 \\ \hline y & 5 & 1 \\ \hline \end{array}$$

Short Answer

Expert verified
The exponential model that fits the given points is \(y = 5 * (\sqrt[4]{1/5})^{x}\).

Step by step solution

01

Formulate the Exponential Equation for Both Points

We can write the exponential model as \(y = ab^{x}\). From the given table, we have two points, (0,5) and (4,1). We substitute these coordinates into our exponential model to set up two equations. From (0,5), the equation becomes \(5 = ab^{0}\), and from (4,1), the equation becomes \(1 = ab^{4}\).
02

Solve the First Equation

Right away, from \(5 = ab^{0}\) we can solve for a because any number (except zero) to the power of zero is 1. Therefore, this gives us \(a = 5\).
03

Substitute the Value of a into the Second Equation

Using the value of a from Step 2, we can solve the second equation \(1 = ab^{4}\) which simplifies to \(1 = 5b^{4}\). By re-arranging this equation, we can solve for b. Divide both sides by 5: \(b^{4} = 1/5\). Then take the fourth root of both sides to get \(b = \sqrt[4]{1/5}\).
04

Verify the Solution

To verify that a = 5 and b = \(\sqrt[4]{1/5}\) satisfy the exponential model, you substitute the values of a and b back into the model formula \(y = 5 * (\sqrt[4]{1/5})^{x}\) and check if it gives the y-values according to the given x-values in the table.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve the equation algebraically. Round your result to three decimal places. Verify your answer using a graphing utility. $$\frac{1+\ln x}{2}=0$$

Home Mortgage \(A \$ 120,000\) home mortgage for 30 years at \(7 \frac{1}{2} \%\) has a monthly payment of \(\$ 839.06\) Part of the monthly payment covers the interest charge on the unpaid balance, and the remainder of the payment reduces the principal. The amount paid toward the interest is $$u=M-\left(M-\frac{P r}{12}\right)\left(1+\frac{r}{12}\right)^{12 t}$$ and the amount paid toward the reduction of the principal is $$v=\left(M-\frac{P r}{12}\right)\left(1+\frac{r}{12}\right)^{12 t}$$ In these formulas, \(P\) is the size of the mortgage, \(r\) is the interest rate, \(M\) is the monthly payment, and \(t\) is the time (in years). (a) Use a graphing utility to graph each function in the same viewing window. (The viewing window should show all 30 years of mortgage payments.) (b) In the early years of the mortgage, is the greater part of the monthly payment paid toward the interest or the principal? Approximate the time when the monthly payment is evenly divided between interest and principal reduction. (c) Repeat parts (a) and (b) for a repayment period of 20 years \((M=\$ 966.71) .\) What can you conclude?

Home Mortgage The total interest \(u\) paid on a home mortgage of \(P\) dollars at interest rate \(r\) for \(t\) years is $$u=P\left[\frac{r t}{1-\left(\frac{1}{1+r / 12}\right)^{12 t}}-1\right]$$ Consider a \(\$ 120,000\) home mortgage at \(7 \frac{1}{2} \%\) (a) Use a graphing utility to graph the total interest function. (b) Approximate the length of the mortgage for which the total interest paid is the same as the size of the mortgage. Is it possible that some people are paying twice as much in interest charges as the size of the mortgage?

Use a graphing utility to graph and solve the equation. Approximate the result to three decimal places. Verify your result algebraically. $$e^{0.09 t}=3$$

Writing a Natural Logarithmic Equation In Exercises \(53-56,\) write the exponential equation in logarithmic form. $$e^{1 / 2}=1.6487 \ldots$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.