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Solve the exponential equation algebraically. Approximate the result to three decimal places. $$6^{x}+10=47$$

Short Answer

Expert verified
The approximate solution to the equation is \(x = 2.279\)

Step by step solution

01

Isolate the Exponential Term

Start by subtracting 10 from both sides of the equation. This gives us the equation \(6^{x}=37\)
02

Apply Natural Logarithm

Next, apply the natural logarithm to both sides of the equation to get rid of the base 6. This gives us the equation \(\ln(6^{x}) =\ln(37)\)
03

Simplify Left Hand Side

By properties of logarithms, on the left side we can bring the exponent (x) down as a coefficient to give: \(x \cdot \ln(6) = \ln(37)\)
04

Isolate x

Now, divide both sides of the equation by \(\ln(6)\) to isolate x. This gives us \(x = \frac{\ln(37)}{\ln(6)}\)
05

Use a Calculator to Calculate the Value of x

Use a calculator to find the numerical value of x, approximated to three decimal places.
06

Solve for x

Given \(x = \frac{\ln(37)}{\ln(6)}\), calculate the result to three decimal digits. Make sure the calculator mode is in natural logarithm mode, not common logarithms (log base 10)

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