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Use synthetic division to verify the upper and lower bounds of the real zeros of \(f\) \(f(x)=x^{4}-4 x^{3}+16 x-16\) (a) Upper: \(x=5\) (b) Lower: \(x=-3\)

Short Answer

Expert verified
By using synthetic division, we verified that \(x=5\) is indeed an upper bound and \(x=-3\) is a lower bound for the real zeros of the given polynomial function.

Step by step solution

01

Understanding synthetic division

Synthetic division is a shortcut method to divide a polynomial by a linear polynomial of the form \(x-a\). It simplifies the process by only using the coefficients of the polynomials.
02

Synthetic division for upper bound (x = 5)

First, we arrange the polynomial in descending order with \[f(x)=x^{4}-4 x^{3}+0x^{2}+16 x-16\]. Always remember to include zero in your synthetic division if necessary. Then, let's set up the synthetic division with '5' at the box and carry out the operations: \[\begin{{array}}{{r|rrrrr}}5 & 1 & -4 & 0 & 16 & -16 \ & & 5 & 5 & 25 & 125 \\hline & 1 & 1 & 5 & 41 & 109 \\end{{array}}\]All signs are positive, so x=5 is an upper bound.
03

Synthetic division for lower bound (x = -3)

Setting up the synthetic division with '-3' at the box and carry out the operations:\[\begin{{array}}{{r|rrrrr}}-3 & 1 & -4 & 0 & 16 & -16 \ & & -3 & 21 & -63 & 141 \\hline & 1 & -7 & 21 & -47 & 125 \\end{{array}}\]The signs are alternating, indicating x=-3 is a lower bound.

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