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Simplify the complex number and write it in standard form. $$4 i^{2}-2 i^{3}$$

Short Answer

Expert verified
The simplified form of the complex number \(4 i^{2}-2 i^{3}\) in standard form is \(-4 + 2i\)

Step by step solution

01

Substitute \(i^{2}\) and \(i^{3}\) with their values

Replace \(i^{2}\) with -1 and \(i^{3}\) with -i. Our expression becomes: \(4*(-1)-2*(-i) => -4 + 2i\)
02

Verify the result

Double-check if the result is in standard form, which is \(a + bi\). Here, a = -4 and b = 2, thus it is in the standard form of a complex number.

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Most popular questions from this chapter

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