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The revenue and cost equations for a product are \(R=x(75-0.0005 x)\) and \(C=30 x+250,000,\) where \(R\) and \(C\) are measured in dollars and \(x\) represents the number of units sold. How many units must be sold to obtain a profit of at least \(\$ 750,000 ?\) What is the price per unit?

Short Answer

Expert verified
The calculations for the exact number of units that need to be sold and the price per unit are dependent on the specifics of the solution to the inequality and therefore cannot be answered directly here. Generally, two tasks need to be performed to answer these questions: Firstly, the inequality has to be solved algebraically for \(x\). Secondly, \(x\) has to be put into the revenue function and the resulting \(R\) divided by \(x\).

Step by step solution

01

Set up the profit equation

Profit is calculated as revenue minus cost. Using the given equations for revenue (\(R=x(75-0.0005 x)\)) and cost (\(C=30x+250,000\)), the profit (\(P\)) can be calculated by the equation \(P = R - C\). Integrating the given equations into this formula leads to \(P = x(75-0.0005x) - (30x+250,000)\).
02

Calculate the number of units for a profit of at least $750,000.

To find out how many units have to be sold to reach a profit of at least $750,000, set up an inequality: \(P \geq 750,000\). Solve this inequality (\(x(75-0.0005x) - (30x+250,000) \geq 750,000\)) for \(x\).
03

Calculate the price per unit

To find the price per unit, substitute the number of units obtained in step 2 into the revenue function \(R=x(75-0.0005 x)\). Solve this equation for \(R\), then divide \(R\) by \(x\) to get the price per unit.

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