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Solve the inequality. Then graph the solution set. $$\frac{5+7 x}{1+2 x} \leq 4$$

Short Answer

Expert verified
The interval solution is \( [-\frac{1}{2},-\frac{1}{3}) \)

Step by step solution

01

Setup

Start by isolating the inequality: \( \frac{5+7x}{1+2x} - 4 \leq 0 \). This simplifies to \( \frac{5+7x-4(1+2x)}{1+2x} \leq 0 \).
02

Simplify inequality

After expanding and simplifying, we get \( \frac{-3x+1}{1+2x} \leq 0 \).
03

Find Critical Points

The critical points will be where the numerator or the denominator is zero. Setting both to zero gives us \( x = -\frac{1}{3} \) and \( x = -\frac{1}{2} \).
04

Test Intervals

Now divide the number line using the critical points and test each interval in the inequality. We choose test points \(-1\),\(-\frac{2}{5}\), \(0\) for intervals \(x <-\frac{1}{2}\), \(-\frac{1}{2}-\frac{1}{3}\) respectively. Substituting these values in gives -\( \frac{2}{2}<0 \) (True), -\( \frac{20}{14}<0 \) (True), -\( \frac{2}{2}<0 \) (True). Therefore, all values between these restrictions are valid solutions.
05

Plot the solution

Lastly, plot these intervals on a number line. Indicate the included endpoints with a solid circle, and the excluded endpoints with an open circle.

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