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Solve the inequality. Then graph the solution set. $$x^{2}+2 x>3$$

Short Answer

Expert verified
The solution to the inequality \(x^{2}+2x-3 > 0\) is (-∞,-3) U (1,∞).

Step by step solution

01

Simplification

Start by subtracting 3 from both sides of the equation to form a quadratic inequality \(x^{2}+2x-3 > 0\).
02

Factoring the quadratic inequality

The quadratic inequality can be factored into \((x - 1)(x + 3) > 0\).
03

Finding the critical points

Next, we find the root of the factored inequality as \(x = 1\) and \(x = -3\).
04

Testing the intervals

Then, we test the intervals (-∞, -3), (-3, 1) and (1, ∞). Taking test points as -4 for (-∞, -3), 0 for (-3, 1) and 2 for (1, ∞). Substituting in equation \((x - 1)(x + 3) > 0\), we see that the inequality is > 0 for (-∞, -3) and (1, ∞).
05

Interval notation and graph

Finally, the solution of \(x^{2}+2x-3 > 0\) can be written in interval notation as (-∞,-3) U (1,∞). The graph will be a number line with open circles at -3 and 1, with shading to the left of -3 and to the right of 1.

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