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If \(f\) is an even function, determine whether \(g\) is even, odd, or neither. Explain. (a) \(g(x)=-f(x)\) (b) \(g(x)=f(-x)\) (c) \(g(x)=f(x)-2\) (d) \(g(x)=f(x-2)\)

Short Answer

Expert verified
(a) \(g(x)=-f(x)\) is odd. (b) \(g(x)=f(-x)\) is even. (c) \(g(x)=f(x)-2\) is even. (d) \(g(x)=f(x-2)\) is neither even nor odd.

Step by step solution

01

(a) Checking if \(g(x)=-f(x)\) is even, odd, or neither

Since \(f\) is an even function, we know that \(f(-x)=f(x)\). If we substitute \(x\) with \(-x\) in \(g(x)=-f(x)\), we obtain \(g(-x)=-f(-x)\). As \(f\) is even, we can substitute \(f(-x)\) to \(f(x)\) to get \(g(-x)=-f(x)\), which matches the \(g(x)\). Hence, \(g(x)\) is an odd function in this case.
02

(b) Checking if \(g(x)=f(-x)\) is even, odd, or neither

We are given that \(f\) is an even function, so \(f(-x)=f(x)\). So, \(g(x) = f(-x)\) can be rewritten as \(g(x) = f(x)\). If we apply the transformation \(x to -x\) we get \(g(-x) = f(-(-x)) = f(x)\), which is identical to \(g(x)\). Hence, \(g(x)\) is also an even function.
03

(c) Checking if \(g(x)=f(x)-2\) is even, odd, or neither

As given \(f\) is even, let's apply the transformation \(x to -x\) in \(g(x)=f(x)-2\) to get \(g(-x) = f(-x)-2\). As \(f\) is even, we can substitute \(f(-x)\) to \(f(x)\) and we get \(g(-x) = f(x)-2\), which aligns with \(g(x)\). Therefore, \(g(x)\) is also an even function.
04

(d) Checking if \(g(x)=f(x-2)\) is even, odd, or neither

By applying the transformation \(x to -x\) in \(g(x)=f(x-2)\), we get \(g(-x) = f(-x-2)\). This obviously cannot be converted into \(g(x)\) form and hence it is neither even nor odd.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Symmetry of Functions
When analyzing functions, the concept of symmetry plays a critical role, letting us predict a function’s behavior and solve problems more intuitively. For a function to be even, it must display symmetry with respect to the y-axis. This means if you were to fold the graph of the function along the y-axis, both halves would match perfectly. Mathematically, a function is even if for every input value x, the condition \( f(-x) = f(x) \) holds true.

An odd function, on the other hand, has rotational symmetry around the origin. Imagine rotating the graph 180 degrees around the origin; if the function’s graph falls onto itself, it’s described as odd. The defining characteristic of an odd function is that it satisfies the condition \( f(-x) = -f(x) \) for all values of x. The exercise given illustrates how the even property of function \( f \) can influence the symmetry of a new function \( g \), created through various transformations.
Transformation of Functions
Transformations can shift, reflect, stretch, or compress the graph of a function. Common transformations include translations (shifting the graph horizontally or vertically), reflections (flipping the graph across an axis), and scaling (changing the graph’s size).

Understanding how transformations affect the symmetry of a function is crucial. For instance, multiplying a function by a constant, as seen in part (a) of the exercise, results in a reflection if the constant is negative. This is why \( g(x) = -f(x) \) changes an even function to an odd one; it reflects the graph over the x-axis, altering its symmetry. On the other hand, part (b) shows that replacing \( x \) with \( -x \) in an even function does not change its symmetry, effectively creating a new function that is also even.
Analyzing Function Properties
In addition to symmetry, other properties such as periodicity, range, and domain are essential when analyzing functions. These attributes can sometimes be deduced by examining the algebraic form of the function and applying known properties. For example, as seen in part (c), subtracting a constant from an even function \( f(x) \) does not affect its evenness because the symmetry with respect to the y-axis remains unaltered.

However, in part (d), the horizontal translation by subtracting 2 from \( x \) before it is input into \( f \) results in a function that is not symmetric about the y-axis or origin. Such analysis is invaluable for understanding how functions behave and how they can be manipulated to suit various mathematical or practical requirements.
Precalculus
Precalculus serves as the groundwork for understanding the mathematics involved in calculus. It covers a variety of topics such as functions, symmetry, transformations, and the analysis of their properties. The exercise provided falls into the realm of precalculus and aids in solidifying a student's understanding of how different kinds of functions behave and how we can characterize them as even, odd, or neither.

Precalculus emphasizes the foundational knowledge required for calculus but also delivers a deep understanding of key concepts needed in many fields of mathematics and science. Through exercises such as these, students gain the skills to approach more complex problems with a strong mathematics toolkit.

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Most popular questions from this chapter

Beam Load The maximum load that can be safely supported by a horizontal beam varies jointly as the width of the beam and the square of its depth and inversely as the length of the beam. Determine the changes in the maximum safe load under the following conditions. A. The width and length of the beam are doubled. B. The width and depth of the beam are doubled.

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