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Find the center and radius of the circle. Then sketch the graph of the circle. $$(x-2)^{2}+(y+3)^{2}=\frac{16}{9}$$

Short Answer

Expert verified
The center of the circle is at (2,-3) and its radius is \(\frac{4}{3}\).

Step by step solution

01

Identification of the Parameters

By comparing the equation \((x-2)^{2}+(y+3)^{2}=\frac{16}{9}\) with the standard form, we can determine the center \((h,k)\) of the circle to be \((2,-3)\)
02

Finding the radius

The radius \(r\) of the circle can be found by square rooting the right side of the equation, \(r=\sqrt{\frac{16}{9}}\). This gives us the radius \(r=\frac{4}{3}\).
03

Sketching the Graph

To draw the graph, start by marking the center point at (2,-3) on the cartesian plane. From there, draw a circle with a radius of \(\frac{4}{3}\) units. Make sure the circle is as round as possible and that it touches the points on the x and y axis that are \(\frac{4}{3}\) units away from the center.

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