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(a) find the inverse function of \(f\) (b) graph both \(f\) and \(f^{-1}\) on the same set of coordinate axes, (c) describe the relationship between the graphs of \(f\) and \(f^{-1},\) and (d) state the domains and ranges of \(f\) and \(f^{-1}\). $$f(x)=\frac{x+1}{x-2}$$

Short Answer

Expert verified
The inverse function of \(f(x) = \frac{x+1}{x-2}\) is \(f^{-1}(x) = \frac{2x+1}{x-1}\). The graphs of \(f(x)\) and \(f^{-1}(x)\) are reflections of each other over the line \(y=x\). The domain and range of \(f(x)\) are all real numbers except \(x = 2\) and \(y = 1\) respectively. The domain and range of \(f^{-1}(x)\) are all real numbers except \(x = 1\) and \(y = 2\) respectively.

Step by step solution

01

Find the inverse function of \(f\)

Given \(f(x)=\frac{x+1}{x-2}\), the first step to find its inverse, denoted as \(f^{-1}(x)\), is to switch \(x\) and \(y\) in the equation. This gives them \(x=\frac{y+1}{y-2}\). Then clarify \(x\) in terms of \(y\), which results in \(x(y-2) = y + 1\), it simplifies to \(xy-2x = y + 1\). This can be rearranged to give \(y = \frac{2x+1}{x-1}\), so \(f^{-1}(x) = \frac{2x+1}{x-1}\).
02

Graph the functions

The next task is to graph both functions \(f\) and \(f^{-1}\) on the same set of coordinate axes. For \(f(x)\), plot some points like (-1, -2/3), (0, -1/2), (1, 2), (3, 4). For \(f^{-1}(x)\), some points could be (-1, -3), (0, -1), (1, 3), (2, 5). The vertical asymptotes for \(f(x)\) is at \(x = 2\) and for \(f^{-1}(x)\) is at \(x = 1\) which should be indicated by dashed lines.
03

Describe the relationship between the graphs

The function and its inverse \(f\) and \(f^{-1}\) are reflections of each other over the line \(y=x\). This is a basic property of functions and their inverses and can be visually verified on the graph.
04

State the domains and ranges of \(f\) and \(f^{-1}\)

For function \(f\), defined by \(f(x) = \frac{x+1}{x-2}\), the domain is all real numbers except \(x = 2\), and the range is also all real numbers except \(y = 1\). For the inverse function \(f^{-1}(x) = \frac{2x+1}{x-1}\), the domain is all real numbers except \(x = 1\), and the range is all real numbers except \(y = 2\).
05

Conclusion

The function \(f(x)\) and its inverse \(f^{-1}(x)\) provide reflections of each other across the line \(y=x\), are not defined at the values of \(x = 2\) and \(x = 1\) and have asymptotes at those points respectively. This is observed in their domains and ranges where points of discontinuity and non-existence occur.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain and Range
The **domain** of a function includes all possible inputs (x-values) that will give a real number output. Conversely, the **range** encompasses all possible outputs (y-values) from the function.
For the function \(f(x)=\frac{x+1}{x-2}\), the domain is restricted because division by zero is undefined. Therefore, \(f(x)\) is not defined at \(x = 2\), making the domain all real numbers except \(x = 2\).
The range of \(f(x)\) excludes \(y = 1\) because regardless of which x-value is used (except \(x=2\)), the function cannot output a value of 1. This is due to properties of the function's asymptote which will be discussed further.
Moving to its inverse \(f^{-1}(x)=\frac{2x+1}{x-1}\), similar logic is applied. Here, the domain includes all real numbers except \(x = 1\), as division by zero again is undefined.
Consequently, the range of \(f^{-1}(x)\) would exclude \(y = 2\). Understanding domains and ranges is crucial for graphing and identifying where functions might not exist.
Graphing Functions
Graphing a function involves plotting its possible outputs (y-values) against its inputs (x-values). This gives a visual representation of what the function does.
For the function \(f(x) = \frac{x+1}{x-2}\), a few key points like \((-1, -\frac{2}{3})\), \((0, -\frac{1}{2})\), and \((3, 4)\) can help sketch the curve. It is important to note the vertical asymptote at \(x = 2\), which indicates a point where the function is undefined. This is often shown as a dashed line on the graph.
When graphing \(f^{-1}(x)=\frac{2x+1}{x-1}\), points like \((-1, -3)\), \((0, -1)\), and \((2, 5)\) can guide the curve. It has its vertical asymptote at \(x=1\).
Visual graphs for both functions \(f(x)\) and \(f^{-1}(x)\) on the same axes provide insight into their behavior and range of values. Accurately plotting these functions aids in understanding their properties and any restrictions.
Reflection Across the Line y=x
A key relationship between a function and its inverse is their symmetry concerning the line \(y = x\). This line acts as a mirror, reflecting the graph of a function into its inverse.
If you mentally trace the line \(y=x\) on a graph containing both \(f(x)\) and \(f^{-1}(x)\), you'll observe that each point \((a, b)\) on \(f(x)\) has a corresponding point \((b, a)\) on \(f^{-1}(x)\).
This property occurs because, in order for two functions to be inverses, swapping their x and y coordinates will yield the other function.
The symmetry is not just a visual cue but mathematically signifies that the composite functions \(f(f^{-1}(x))\) and \(f^{-1}(f(x))\) will both equal \(x\).
Observing these reflections on the graph can help confirm the correctness of an inverse, ensuring that it reflects exactly over \(y=x\). This understanding is fundamental when learning about functions and their inverses.

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