/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 (a) find the inverse function of... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) find the inverse function of \(f\) (b) graph both \(f\) and \(f^{-1}\) on the same set of coordinate axes, (c) describe the relationship between the graphs of \(f\) and \(f^{-1},\) and (d) state the domains and ranges of \(f\) and \(f^{-1}\). $$f(x)=x^{5}-2$$

Short Answer

Expert verified
The inverse function of \(f(x) = x^{5} - 2\) is \(f^{-1}(x) = (x + 2) ^ {(1/5)}\). The graph of \(f^{-1}(x)\) is a reflection of \(f(x)\) across the line \(y = x\). The domain of \(f(x)\) is all real numbers, and its range is all real numbers. The domain of \(f^{-1}(x)\) is \(x \geq -2\), and its range is all real numbers.

Step by step solution

01

Find the Inverse Function

The inverse function \(f^{-1}(x)\) is found by swapping the positions of \(y\) and \(x\) and resolving the equation in term of \(y\). So, \(x = y^{5}-2\). Adding 2 to both sides gives \(x + 2 = y^{5}\). Taking the fifth root of each side, we find the inverse function \(f^{-1}(x) = (x + 2) ^ {(1/5)}.\)
02

Graphing the Functions

To graph the functions, first graph the original function \(f(x) = x^{5} - 2\) using a variety of \(x\)-values. Then, graph the inverse function, \(f^{-1}(x) = (x + 2) ^ {(1/5)}\), using the same \(x\)-values. It's important to note that the graph of the inverse function will be the reflection of the graph of the original function across the line \(y = x\).
03

Describe the Relationship

The graph of the inverse function is a reflection of the graph of the original function across the line \(y = x\). They are symmetrical about this line.
04

State the Domains and Ranges

The domain of a function is the set of all possible input values while the range is the set of all possible output values. For the original function \(f(x) = x^{5} - 2\), the domain and range are all real numbers since \(x^{5}\) as a polynomial has the set of all real numbers as domain and the subtraction doesn't restrict the domain nor the range. For the inverse function \(f^{-1}(x) = (x + 2) ^ {(1/5)}\), the domain is \(x \geq -2\) because \(x\) must be greater than or equal to -2 to allow real number outputs (can’t take the fifth root of a negative number), and the range is all real numbers, since there's no restriction on the outputs from the formula.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Functions
Understanding how to represent a function visually with a graph is a fundamental skill in mathematics. A graph provides a picture of how a function behaves and how its values change with different inputs. To graph a given function like the one in our exercise, \(f(x) = x^{5} - 2\), we can create a table of values by selecting a range of \(x\)-values and calculating the corresponding \(y\)-values (or \(f(x)\)). Then, plot these points on a coordinate plane and draw a curve through them to visualize the function's behavior.

When graphing, consider the scale and the range of the \(x\)-values to best depict the nature of the function. For a polynomial function like the one provided, which has a single term raised to an odd power, we expect to see a graph that passes through the origin (if it's not shifted by a constant like -2) and extends infinitely in both the positive and negative directions for \(y\). This graph also aids in visualizing subsequent concepts such as inverse functions and symmetry.
Symmetry in Graphs
Graphical symmetry plays an important role in understanding functions and their inverses. The graphs of a function and its inverse are mirror images of each other along the line \(y = x\). This line acts as a mirror reflecting the original function to its inverse.

An important note is that not all functions have inverses. For a function to have an inverse, each input must lead to only one output (the function must be one-to-one). The graphical test for finding if a function is one-to-one involves checking if any horizontal line intersects the graph more than once. If it does, the function does not pass the Horizontal Line Test and does not have an inverse that is also a function.

In our exercise, the original function is a quintic polynomial, which is always one-to-one. Its inverse, therefore, also exists and can be observed as a reflection across the line \(y = x\). This relation creates a symmetry that provides a visually compelling confirmation of the inverse relationship.
Domain and Range of a Function
The domain of a function encapsulates all the possible input values (\(x\)-values) that the function can accept. Determining the domain includes identifying any restrictions such as divisions by zero or even roots of negative numbers in the context of real numbers.

Conversely, the range represents all possible outputs (\(y\)-values) that the function can produce. For polynomial functions, as in our exercise, the domain is all real numbers since there's no restriction on the input values. However, the range for other types of functions may be limited by factors such as square roots or logarithms.

In the case of inverse functions, the domain and range interplay uniquely. The range of the function becomes the domain of its inverse, and the domain of the function turns into the range of the inverse. Hence, for our initial function \(f(x) \), we have a domain and range of all real numbers, while for its inverse \(f^{-1}(x) = (x + 2) ^ {(1/5)}\), the domain is restricted to \(x \geq -2\) and the range is all real numbers—as we can take the fifth root of a positive number or zero.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The cost of sending an overnight package from New York to Atlanta is 26.10 dollars for a package weighing up to, but not including, 1 pound and 4.35 dollars for each additional pound or portion of a pound. (a) Use the greatest integer function to create a model for the cost \(C\) of overnight delivery of a package weighing \(x\) pounds, \(x>0\). (b) Sketch the graph of the function.

During a nine-hour snowstorm, it snows at a rate of 1 inch per hour for the first 2 hours, at a rate of 2 inches per hour for the next 6 hours, and at a rate of 0.5 inch per hour for the final hour. Write and graph a piecewise- defined function that gives the depth of the snow during the snowstorm. How many inches of snow accumulated from the storm?

A company produces a product for which the variable cost is 12.30 dollars per unit and the fixed costs are 98,000 dollars. The product sells for 17.98 dollars. Let \(x\) be the number of units produced and sold. (a) The total cost for a business is the sum of the variable cost and the fixed costs. Write the total cost \(C\) as a function of the number of units produced. (b) Write the revenue \(R\) as a function of the number of units sold. (c) Write the profit \(P\) as a function of the number of units sold. (Note: \(P=R-C\) ).

Find a mathematical model that represents the statement. (Determine the constant of proportionality.) Use Hooke's Law for springs, which states that the distance a spring is stretched (or compressed) varies directly as the force on the spring.

Decide whether the statement is true or false. Justify your answer. A. Given that \(y\) varies directly as the square of \(x\) and \(x\) is doubled, how will \(y\) change? Explain. B. Given that \(y\) varies inversely as the square of \(x\) and \(x\) is doubled, how will \(y\) change? Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.