/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Graphing a Linear Equation In Ex... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 1: Problem 15

Graphing a Linear Equation In Exercises \(15-24\) find the slope and \(y\) -intercept (if possible) of the equation of the line. Sketch the line. $$y=5 x+3$$

Short Answer

Expert verified
The slope (m) is 5 and the y-intercept (c) is 3. The line passes through the point (0,3) and rises 5 units for every 1 unit it runs to the right.

Step by step solution

01

Find the Slope

The coefficient of 'x' in the equation 'y = 5x + 3' is the slope. So, the slope (m) is 5.
02

Find the y-Intercept

The y-intercept is the constant term in the equation 'y = 5x + 3'. So, the y-intercept (c) is 3.
03

Sketch the line

To sketch the line, start at the y-intercept point (0,3) on the y-axis and use the slope to find the next point. Slope is the rise (vertical change) over run (horizontal change). Since the slope is 5, for every 1 unit you move to the right, move 5 units up. Keep plotting points and drawing a line through them.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write a sentence using the variation terminology of this section to describe the formula. Surface area of a sphere: \(S=4 \pi r^{2}\)

The work \(W\) done when lifting an object varies jointly with the object's mass \(m\) and the height \(h\) that the object is lifted. The work done when a 120 -kilogram object is lifted 1.8 meters is 2116.8 joules. How much work is done when lifting a 100 -kilogram object 1.5 meters?

Match the data with one of the following functions $$f(x)=c x, g(x)=c x^{2}, h(x)=c \sqrt{|x|}, \quad \text {and} \quad r(x)=\frac{c}{x}$$ and determine the value of the constant \(c\) that will make the function fit the data in the table. $$\begin{array}{|c|c|c|c|c|c|}\hline x & -4 & -1 & 0 & 1 & 4 \\\\\hline y & -1 & -\frac{1}{4} & 0 & \frac{1}{4} & 1 \\\\\hline\end{array}$$

Sketch the graph of the function. $$g(x)=-[[x]]$$

Find a mathematical model that represents the statement. (Determine the constant of proportionality.) Use Hooke's Law for springs, which states that the distance a spring is stretched (or compressed) varies directly as the force on the spring.
See all solutions

Recommended explanations on Math Textbooks

Geometry

Read Explanation

Pure Maths

Read Explanation

Probability and Statistics

Read Explanation

Mechanics Maths

Read Explanation

Statistics

Read Explanation

Discrete Mathematics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.