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Find the angle \(\theta\) (in radians and degrees) between the lines. \(x+2 y=8\) \(x-2 y=2\)

Short Answer

Expert verified
The angle \(\theta\) between the two lines is approximately \(-\frac{\pi}{2}\) radians or -90 degrees.

Step by step solution

01

Find the slope for both lines

The slope of the line can be found from the equation in slope-intercept form \(y=mx+b\), where m is the slope. For the first line, rearranging gives \(y = -\frac{1}{2}x + 4\). Hence the slope \(m1 = -\frac{1}{2}\). For the second line, rearranging gives \(y = \frac{1}{2}x + 1\). Hence the slope \(m2 = \frac{1}{2}\).
02

Substitute the slopes to the formula

Substitute \(m1\) and \(m2\) into the formula \[\theta = \arctan\left(\frac{m1-m2}{1+m1 \cdot m2}\right)\] This gives \[\theta = \arctan\left(\frac{-\frac{1}{2} - \frac{1}{2}}{1 + (-\frac{1}{2})\times\frac{1}{2}}\right) = \arctan(-\infty)\]
03

Simplify to get the angle in radians

\[\theta = \arctan(-\infty) \approx -\frac{\pi}{2}\] Note that if the result is negative, it means that the angle is measured in the opposite direction.
04

Convert the angle to degrees

\[\theta = -\frac{180}{\pi} \times \frac{\pi}{2} = -90 ^\circ\]

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