Chapter 6: Problem 27
Identify the conic and sketch its graph. \(r=\frac{4}{2-\cos \theta}\)
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Chapter 6: Problem 27
Identify the conic and sketch its graph. \(r=\frac{4}{2-\cos \theta}\)
These are the key concepts you need to understand to accurately answer the question.
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(d) Explain how the result of part (c) can be used as a sketching aid when graphing parabolas. Consider the parabola \(x^{2}=4 p y\) (a) Use a graphing utility to graph the parabola for \(p=1, p=2, p=3,\) and \(p=4\). Describe the effect on the graph when \(p\) increases. (b) Locate the focus for each parabola in part (a). (c) For each parabola in part (a), find the length of the latus rectum (see figure). How can the length of the latus rectum be determined directly from the standard form of the equation of the parabola?
Use a graphing utility to graph the ellipse. Find the center, foci, and vertices. (Recall that it may be necessary to solve the equation for \(y\) and obtain two equations.) \(36 x^{2}+9 y^{2}+48 x-36 y-72=0\)
Identify the conic as a circle or an ellipse. Then find the center, radius, vertices, foci, and eccentricity of the conic (if applicable), and sketch its graph. \(\frac{x^{2}}{5}+\frac{y^{2}}{9}=1\)
Describe the relationship between circles and ellipses. How are they similar? How do they differ?
A simply supported beam is 12 meters long and has a load at the center (see figure). The deflection of the beam at its center is 2 centimeters. Assume that the shape of the deflected beam is parabolic. (a) Write an equation of the parabola. (Assume that the origin is at the center of the deflected beam.) (b) How far from the center of the beam is the deflection equal to 1 centimeter?
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