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Use the trigonometric substitution to write the algebraic expression as a trigonometric function of \(\boldsymbol{\theta},\) where \(0<\boldsymbol{\theta}<\pi / 2\) $$\sqrt{x^{2}+25}, \quad x=5 \tan \theta$$

Short Answer

Expert verified
Using the trigonometric substitution \(x = 5 \tan \theta\), the given expression \(\sqrt{x^2 + 25}\) can be rewritten as \(5\sec \theta\)

Step by step solution

01

Substituting the given x value

Start the exercise by substituting \(x = 5 \tan \theta\) into the given expression. Thus, \(\sqrt{x^2 + 25} = \sqrt{(5 \tan \theta)^2 + 25}\)
02

Simplifying the expression

Simplify the expression after substitution. Therefore, \(\sqrt{(5 \tan \theta)^2 + 25} = \sqrt{25 \tan^2 \theta + 25}\)
03

Factoring the expression

The expression under the square root can be factored as 25 times the quantity \(\tan^2 \theta + 1\). Thus, \(\sqrt{25 \tan^2 \theta + 25} = \sqrt{25(\tan^2 \theta + 1)}\)
04

Applying trigonometric identity

Apply the trigonometric identity \(\tan^2 \theta + 1 = \sec^2 \theta\) to replace \(tan^2 \theta + 1\) with \(\sec^2 \theta\). Hence, \(\sqrt{25(\tan^2 \theta + 1)} = \sqrt{25 \sec^2 \theta}\)
05

Simplifying the expression to get the final result

Calculate the square root, which will result in \(5\sec \theta\) as your final answer. Hence, \(\sqrt{25 \sec^2 \theta} = 5 \sec \theta\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

algebraic expression
An **algebraic expression** is a combination of numbers, variables, and operations like addition, subtraction, multiplication, and division. In the exercise, we deal with the expression \( \sqrt{x^2 + 25} \). Here, the variable \( x \) and the constant 25 are part of an algebraic expression within a square root. To transform this expression using trigonometric substitution, we first substitute \( x = 5 \tan \theta \). This substitution bridges algebraic expressions with trigonometric functions, allowing us to simplify the problem. This transformation is particularly useful when dealing with complex algebraic expressions that involve square roots. It's important to get comfortable with identifying and rewriting algebraic expressions in ways that facilitate problem-solving, especially when linking them to trigonometric concepts. Identifying which substitutions to make is key.
trigonometric identity
A **trigonometric identity** is an equation that holds for all values of the involved trigonometric functions for which both sides are defined. In this exercise, we use the identity \( \tan^2 \theta + 1 = \sec^2 \theta \). This identity is crucial in transforming the expression under the square root we derived after substitution, from \( \tan^2 \theta + 1 \) to \( \sec^2 \theta \). Using identities allows us to simplify expressions and make calculations more manageable. To fully grasp trigonometric identities, practice recognizing and applying them. These identities often become tools in solving integrals, derivatives, and other trigonometric transformations. They are the fundamental principles that simplify complex relationships between trigonometric functions.
trigonometric function
**Trigonometric functions** such as sine, cosine, tangent, and their reciprocals, play a significant role in mathematics, especially in relating geometric values to algebraic expressions. In this case, we use the tangent and secant functions. The substitution \( x = 5 \tan \theta \) brings the tangent function into play, which is appropriate given the original expression setup. The resulting expression was linked to the secant function \( \sec \theta \) through \( \sec^2 \theta \) after using the identity \( \tan^2 \theta + 1 = \sec^2 \theta \). This conversion allows the final expression of \( 5 \sec \theta \) to emerge.Understanding these functions and their properties is essential as they help navigate between algebraic and trigonometric realms, making complex calculations more accessible.
simplifying expressions
**Simplifying expressions** involves reducing them to their simplest form. It's a crucial step in solving mathematical problems because it provides a clearer, more manageable representation of equations or expressions.In the exercise, after substituting and applying the trigonometric identity, we had \( \sqrt{25 \sec^2 \theta} \). Simplifying this involved treating the square root and factoring aspects separately, yielding the simplest form \( 5 \sec \theta \). Key strategies include:
  • Identifying like terms or factors that can be combined.
  • Utilizing algebraic and trigonometric identities to rewrite terms.
  • Recognizing patterns that allow for straightforward simplification.
Mastering these techniques helps eliminate unnecessary complexity, thus easing problem-solving.

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Most popular questions from this chapter

A Ferris wheel is built such that the height \(h\) (in feet) above ground of a seat on the wheel at time \(t\) (in minutes) can be modeled by \(h(t)=53+50 \sin \left(\frac{\pi}{16} t-\frac{\pi}{2}\right)\) The wheel makes one revolution every 32 seconds. The ride begins when \(t=0\). (a) During the first 32 seconds of the ride, when will a person on the Ferris wheel be 53 feet above ground? (b) When will a person be at the top of the Ferris wheel for the first time during the ride? If the ride lasts 160 seconds, how many times will a person be at the top of the ride, and at what times?

(a) use a graphing utility to graph the function and approximate the maximum and minimum points on the graph in the interval \([0,2 \pi),\) and (b) solve the trigonometric equation and demonstrate that its solutions are the \(x\) -coordinates of the maximum and minimum points of \(f .\) (Calculus is required to find the trigonometric equation.) Function $$f(x)=\sec x+\tan x-x$$ Trigonometric Equation $$\sec x \tan x+\sec ^{2} x-1=0$$

Find the exact values of the sine, cosine, and tangent of the angle. $$-\frac{13 \pi}{12}$$

The table shows the average daily high temperatures in Houston \(H\) (in degrees Fahrenheit) for month \(t,\) with \(t=1\) corresponding to January. (Source: National Climatic Data Center) $$ \begin{array}{|c|c|} \hline \text { Month, } t & \text { Houston, } \boldsymbol{H} \\ \hline 1 & 62.3 \\ 2 & 66.5 \\ 3 & 73.3 \\ 4 & 79.1 \\ 5 & 85.5 \\ 6 & 90.7 \\ 7 & 93.6 \\ 8 & 93.5 \\ 9 & 89.3 \\ 10 & 82.0 \\ 11 & 72.0 \\ 12 & 64.6 \\ \hline \end{array} $$ (a) Create a scatter plot of the data. (b) Find a cosine model for the temperatures in Houston. (c) Use a graphing utility to graph the data points and the model for the temperatures in Houston. How well does the model fit the data? (d) What is the overall average daily high temperature in Houston? (e) Use a graphing utility to describe the months during which the average daily high temperature is above \(86^{\circ} \mathrm{F}\) and below \(86^{\circ} \mathrm{F}\).

Use inverse functions where needed to find all solutions of the equation in the interval \([0,2 \pi)\). $$2 \cos ^{2} x-5 \cos x+2=0$$

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