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Explain why the equation is not an identity and find one value of the variable for which the equation is not true. $$1+\tan \theta=\sec \theta$$

Short Answer

Expert verified
The equation is not an identity as it's not true for all values of \(\theta\). For example, this equation does not hold true for \(\theta = \frac{\pi}{2}\).

Step by step solution

01

Understand the Trigonometric Identities

The equation given is \(1+\tan\theta=\sec\theta\). In order to test if this is an identity, let's first understand what the trigonometric functions tangent (\(\tan\)) and secant (\(\sec\)) mean. The \(\tan\theta\) function is equivalent to \(\frac{\sin\theta}{\cos\theta}\) and the \(\sec\theta\) function is equivalent to \(\frac{1}{\cos\theta}\).
02

Substitute identities into the equation

We substitute these identities into the initial equation, obtaining: \(1+\frac{\sin\theta}{\cos\theta}=\frac{1}{\cos\theta}\). We simplify this to: \(\frac{1+\sin\theta}{\cos\theta}=\frac{1}{\cos\theta}\)
03

Choose a value for theta that invalidates the equation

We can see that for the equation to hold, \(1+\sin\theta\) must always equal to 1. One of the easy choices for \(\theta\) is any value where \(\sin\theta \neq 0\). Let's choose \(\theta = \frac{\pi}{2}\). Substituting in the equation, we find: \(1+ \sin\frac{\pi}{2}\neq \sec\frac{\pi}{2}\), because \(\sin\frac{\pi}{2} =1 \) and \(\sec\frac{\pi}{2} = \) is undefined. Therefore, the initial equation is not an identity.

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