/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 Simplify the expression algebrai... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Simplify the expression algebraically and use a graphing utility to confirm your answer graphically. $$\cos (\pi+x)$$

Short Answer

Expert verified
\(\cos(\pi + x) = -\cos(x)\). This simplification can be visually confirmed by comparing the graphs of y=\(\cos(x)\) and y=-\(\cos(x)\), where the latter is found to be a reflected version of the former about the x-axis.

Step by step solution

01

Use Cosine Properties

By knowing the property of cosine, we have that: \[\cos(\pi + x) = -\cos(x)\]. The cosine function has a property that \(\cos(\pi + x) = -\cos(x)\). This is due to the fact that \(\cos(\pi + x)\) means that x is shifted by \(\pi\) in the graph which causes the cosine graph to shift, and the value becomes negative.
02

Draw the Graph Using Graphing Utility

Graph the functions y=\(\cos(x)\) and y=-\(\cos(x)\) with the same graphing utility. The graph y=\(\cos(x)\) is a wave oscillating between -1 and 1, starting at 1. When \(\pi\) added to x, it becomes y=-\(\cos(x)\) which flips the graph upside down.
03

Confirm Graphically

By comparing the two graphs, it can be seen that y=-\(\cos(x)\) is the reflection of y=\(\cos(x)\) about the x-axis, confirming our initial calculation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.