/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Write the expression as the sine... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Write the expression as the sine, cosine, or tangent of an angle. $$\cos 3 x \cos 2 y+\sin 3 x \sin 2 y$$

Short Answer

Expert verified
The expression \( \cos 3x \cos 2y+ \sin 3x \sin 2y \) can be written in terms of the cosine function as \( \cos(3x + 2y) \)

Step by step solution

01

Recognize the trigonometric identity

First recognize the trigonometric identity \( \cos(A+B)= \cos A \cos B+ \sin A \sin B \). If you look closely, the given expression appears to be in this format.
02

Identify A and B

From the given expression, identify variables that can be represented as A and B. In our case, these would be 3x and 2y.
03

Apply the identity

Now, taking A as \(3x\) and B as \(2y\), our given expression \( \cos 3x \cos 2y+\sin 3x \sin 2y \) can be written as \( \cos(A + B) = \cos(3x + 2y) \)

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