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91Ó°ÊÓ

Write the expression as the sine, cosine, or tangent of an angle. $$\frac{\tan 140^{\circ}-\tan 60^{\circ}}{1+\tan 140^{\circ} \tan 60^{\circ}}$$

Short Answer

Expert verified
The given expression simplifies to \( \tan 80^{\circ} \).

Step by step solution

01

Identify the formula

Recognize the given expression matches the formula for the tangent of the difference of two angles: \( \tan (A-B) = \frac{\tan A-\tan B}{1+\tan A \tan B} \). Here, 140 degrees is A and 60 degrees is B.
02

Apply the formula

Replace A with 140 degrees and B with 60 degrees in the tangent difference formula. This renders \( \tan (140^{\circ}-60^{\circ}) \) as the expression in the given format.
03

Simplify the result

Perform the operation in the parentheses - subtract 60 degrees from 140 degrees, which equals 80 degrees. Thus, the expression \( \tan (140^{\circ}-60^{\circ}) \) simplifies to \( \tan 80^{\circ} \).

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