/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 123 Verify the identity. $$\sin \l... [FREE SOLUTION] | 91Ó°ÊÓ

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Verify the identity. $$\sin \left(\frac{\pi}{6}+x\right)+\sin \left(\frac{\pi}{6}-x\right)=\cos x$$

Short Answer

Expert verified
The identity holds true, as we were able to manipulate the left side to match the right, \( \cos{x} \).

Step by step solution

01

Apply the sum and difference formulas

Use the Sum and Difference Formulas, which state that: \( \sin(\alpha + \beta) = \sin\alpha \cos\beta + \cos\alpha \sin\beta \) and \( \sin(\alpha - \beta) = \sin\alpha \cos\beta - \cos\alpha \sin\beta \). For the problem at hand, this means that: \( \sin \left(\frac{\pi}{6}+x\right) + \sin \left(\frac{\pi}{6}-x\right) = \sin\frac{\pi}{6}\cos{x} + \cos\frac{\pi}{6}\sin{x} + \sin\frac{\pi}{6}\cos{x} - \cos\frac{\pi}{6}\sin{x} \)
02

Simplify the expression

Notice that the terms \( \cos\frac{\pi}{6}\sin{x} \) and \( -\cos\frac{\pi}{6}\sin{x} \) cancel each other out, leaving us with: \( 2\sin\frac{\pi}{6}\cos{x} \)
03

Use known values of trigonometric functions

We know that \( \sin\frac{\pi}{6} = \frac{1}{2} \), so substituting this into the equation gives: \( 2*\frac{1}{2}\cos{x} \) which finally simplifies to \( \cos{x} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sum and Difference Formulas
Understanding the Sum and Difference Formulas is essential for solving a variety of trigonometric problems. These formulas are tools that allow us to express the sine and cosine of a sum or difference of angles in terms of the sine and cosine of each individual angle. Specifically, for sine, the formulas are:
  • \( \sin(\alpha + \beta) = \sin \alpha \cos \beta + \cos \alpha \sin \beta \)
  • \( \sin(\alpha - \beta) = \sin \alpha \cos \beta - \cos \alpha \sin \beta \)
When applied to an equation, these identities help to rewrite trigonometric expressions in an equivalent form that can be more easily analyzed and simplified. For example, in our exercise, we use the Sum Formula to expand \( \sin \left(\frac{\pi}{6}+x\right) \) and the Difference Formula for \( \sin \left(\frac{\pi}{6}-x\right) \). By doing so, the expression is transformed into a form where common trigonometric values can be applied and terms can be canceled to simplify the problem further.
Simplifying Trigonometric Expressions
Simplifying trigonometric expressions is a frequent task in mathematics, which involves reducing expressions to their simplest form using algebraic manipulations and trigonometric identities. This process usually requires the combination of like terms, the use of reciprocal, quotient, or Pythagorean identities, and factoring when possible. In our example, after applying the sum and difference identities, we identify and cancel out the terms that are additive inverses of each other.
For simplification, observe the following steps:
  • Apply relevant trigonometric identities to expand the expressions.
  • Combine like terms and cancel terms where possible.
  • Factor out common factors if applicable.
In the given exercise, after applying the sum and difference formulas, we notice that the \( \cos\frac{\pi}{6}\sin{x} \) term is present with both a positive and negative sign, leading them to cancel each other. This leaves us with a much simpler expression that can be further simplified using known trigonometric values.
Trigonometric Functions Values
The values of trigonometric functions for certain standard angles are fundamental in solving trigonometric problems without a calculator. These angles usually include 0, \( \frac{\pi}{6} \), \( \frac{\pi}{4} \), \( \frac{\pi}{3} \), and \( \frac{\pi}{2} \) radians (or their degree equivalents: 0°, 30°, 45°, 60°, and 90°). Knowing these values:
  • \( \sin \frac{\pi}{6} = \frac{1}{2} \)
  • \( \cos \frac{\pi}{6} = \frac{\sqrt{3}}{2} \)
  • \( \sin \frac{\pi}{4} = \cos \frac{\pi}{4} = \frac{\sqrt{2}}{2} \)
  • \( \sin \frac{\pi}{3} = \frac{\sqrt{3}}{2} \)
  • \( \cos \frac{\pi}{3} = \frac{1}{2} \)
In the exercise, we use the value of \( \sin \frac{\pi}{6} \) to transform the expression into \( 2*\frac{1}{2}\cos{x} \), which simplifies down to just \( \cos{x} \). Recognizing and applying these known values is the final step that completes the process of verifying the trigonometric identity.

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Most popular questions from this chapter

A bridge is to be built across a small lake from a gazebo to a dock (see figure). The bearing from the gazebo to the dock is \(\mathrm{S} 41^{\circ} \mathrm{W}\). From a tree 100 meters from the gazebo, the bearings to the gazebo and the dock are \(\mathrm{S} 74^{\circ} \mathrm{E}\) and \(\mathrm{S} 28^{\circ} \mathrm{E}\), respectively. Find the distance from the gazebo to the dock.

The length \(s\) of a shadow cast by a vertical gnomon (a device used to tell time) of height \(h\) when the angle of the sun above the horizon is \(\theta\) (see figure) can be modeled by the equation \(s=\frac{h \sin \left(90^{\circ}-\theta\right)}{\sin \theta}\) (a) Verify that the equation for \(s\) is equal to \(h \cot \theta\). (b) Use a graphing utility to complete the table. Let \(h=5\) feet. $$ \begin{array}{|l|l|l|l|l|l|l|} \hline \theta & 15^{\circ} & 30^{\circ} & 45^{\circ} & 60^{\circ} & 75^{\circ} & 90^{\circ} \\ \hline s & & & & & & \\ \hline \end{array} $$ (c) Use your table from part (b) to determine the angles of the sun that result in the maximum and minimum lengths of the shadow. (d) Based on your results from part (c), what time of day do you think it is when the angle of the sun above the horizon is \(90^{\circ} ?\)

A flagpole at a right angle to the horizontal is located on a slope that makes an angle of \(12^{\circ}\) with the horizontal. The flagpole's shadow is 16 meters long and points directly up the slope. The angle of elevation from the tip of the shadow to the sun is \(20^{\circ}\). (a) Draw a triangle to represent the situation. Show the known quantities on the triangle and use a variable to indicate the height of the flagpole. (b) Write an equation that can be used to find the height of the flagpole. (c) Find the height of the flagpole.

Fill in the blanks. The Law of Cosines can be used to establish a formula for finding the area of a triangle called ________ ________ Formula.

A plane flies 810 miles from Franklin to Centerville with a bearing of \(75^{\circ}\). Then it flies 648 miles from Centerville to Rosemount with a bearing of \(32^{\circ}\). Draw a figure that visually represents the situation, and find the straight-line distance and bearing from Franklin to Rosemount.

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