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Compare the logarithmic quantities. If two are equal, explain why. $$\frac{\log _{2} 32}{\log _{2} 4}, \quad \log _{2} \frac{32}{4}, \quad \log _{2} 32-\log _{2} 4$$

Short Answer

Expert verified
The simplified values of the three logarithmic quantities are: 2.5, 3 and 3. Thus, the second and third expressions are equal because their difference simplifies to the same single logarithm term considering the properties of logarithms.

Step by step solution

01

Simplify the first expression

The first quantity is a fraction of two logarithms. Use the logarithmic property \(\log_a(m^n) = n \log_a(m)\). Here, it is easy to see that \(32 = 2^5\) and \(4 = 2^2\). Therefore, we have \(\frac{\log _{2} 2^5}{\log _{2} 2^2} = \frac{5\log _{2}2}{2\log _{2}2}= \frac{5}{2}=2.5\).
02

Simplify the second expression

The second quantity is the logarithm of a quotient. Use the logarithmic property \(\log_a(b/c) = \log_a(b) - \log_a(c)\). So we have: \(\log _{2} \frac{32}{4} = \log _{2} 8 = \log _{2} 2^3 = 3 \log _{2}2 = 3\).
03

Simplify the third expression

The third quantity is the difference of two logarithms. Use the logarithmic property \(\log_a(b) - \log_a(c) = \log_a(b/c)\). So, \(\log _{2} 32-\log _{2} 4 = \log _{2} \frac{32}{4} = \log _{2} 8 = \log _{2} 2^3 = 3 \log _{2}2 =3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Expressions
Logarithmic expressions are mathematical statements that contain logarithms. These expressions are important because they allow us to handle and simplify exponential equations easily. When dealing with logarithmic expressions, it’s crucial to recognize the base of the logarithm, which is the number that is raised to a power to obtain a given number. In these expressions, the base can vary, but a common one is base 10, known as the common logarithm, or base 2, which is often used in computer science and engineering. To solve or compare logarithmic expressions effectively, like in the exercise provided, understanding their structure and properties is needed. Simplifying these expressions can involve rewriting them using known logarithmic identities or using the change of base theorem for comparison or evaluation.
Simplifying Logarithms
Simplifying logarithms is the process of using various properties of logarithms to rewrite them more straightforwardly or calculate their values without a calculator. Here are some common ways to simplify logarithmic expressions:
  • Using the Power Rule: \[ \log_a(m^n) = n \cdot \, \log_a(m) \]This states that you can bring the exponent down in front of the logarithm as a multiplier.
  • Applying the Quotient Rule:\[ \log_a \left( \frac{b}{c} \right) = \log_a(b) - \log_a(c) \]This allows you to separate a single logarithm into the difference of two logs, enabling easier computation.
  • Utilizing the Product Rule:\[ \log_a(bc) = \log_a(b) + \log_a(c) \]Used to expand a single logarithm into the sum of two distinct logarithms.
When simplifying, these rules guide us in transforming complex logarithmic statements into easier formats that highlight their true values or show equivalence, as demonstrated in the solution steps of the exercise.
Logarithmic Rules
Logarithmic rules are foundational tools for manipulating and evaluating logarithmic expressions. The three most critical rules are the Product Rule, the Quotient Rule, and the Power Rule.
  • The Product Rule: This rule states that the logarithm of a product is the sum of the logarithms of the individual factors. It is useful when multiplying numbers inside a log.\[ \log_a(bc) = \log_a(b) + \log_a(c) \]
  • The Quotient Rule: It expresses the logarithm of a quotient as the difference between the logarithms of the numerator and the denominator.\[ \log_a \left( \frac{b}{c} \right) = \log_a(b) - \log_a(c) \]
  • The Power Rule: This allows you to take the exponent in the argument of a logarithm and move it out to the front, turning it into a coefficient.\[ \log_a(m^n) = n \cdot \log_a(m) \]
Understanding these rules is essential for anyone working with logarithms, as they are widely used not just in math, but also in various scientific and engineering fields. They allow for significant simplification and accurate calculations, ensuring precision in both theoretical and practical applications.

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Most popular questions from this chapter

Let \(f(x)=\log _{a} x\) and \(g(x)=a^{x},\) where \(a>1\) (a) Let \(a=1.2\) and use a graphing utility to graph the two functions in the same viewing window. What do you observe? Approximate any points of intersection of the two graphs. (b) Determine the value(s) of \(a\) for which the two graphs have one point of intersection. (c) Determine the value(s) of \(a\) for which the two graphs have two points of intersection.

The sales \(S\) (in thousands of units) of a new CD burner after it has been on the market for \(t\) years are modeled by \(S(t)=100\left(1-e^{k t}\right) .\) Fifteen thousand units of the new product were sold the first year. (a) Complete the model by solving for \(k\). (b) Sketch the graph of the model. (c) Use the model to estimate the number of units sold after 5 years.

Find the exponential model \(y=a e^{b x}\) that fits the points shown in the graph or table. $$ \begin{array}{|l|l|l|} \hline x & 0 & 4 \\ \hline y & 5 & 1 \\ \hline \end{array} $$

Solve the logarithmic equation algebraically. Approximate the result to three decimal places. $$\ln x+\ln (x-2)=1$$

If $$\$ 1$$ is invested in an account over a 10-year period, the amount in the account, where \(t\) represents the time in years, is given by \(A=1+0.075 \llbracket t \rrbracket\) or \(A=e^{0.07 t}\) depending on whether the account pays simple interest at \(7 \frac{1}{2} \%\) or continuous compound interest at \(7 \%\). Graph each function on the same set of axes. Which grows at a higher rate? (Remember that \(\llbracket t \rrbracket\) is the greatest integer function discussed in Section 1.6.)

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