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Condense the expression to the logarithm of a single quantity. $$-4 \log _{6} 2 x$$

Short Answer

Expert verified
The condensation of the expression results in \( \log_{6} \frac{1}{16x^4} \).

Step by step solution

01

Apply the Power Rule of Logarithms

The power rule of logarithms states that \( \log_b {(m^n)} = n \log_b m \). This rule allows us to move coefficients in front of the logarithm and make them exponents of the argument inside the log. In this case, we move the coefficient -4 inside the logarithm as a power, this gives us: \( \log_{6} (2x)^{-4} \).
02

Apply the Rule of Exponents

We now have \( \log_{6} (2x)^{-4} \). To make it simpler, we can apply the rule of exponents which states \( m^{-n} = 1/m^n \). This gives us: \( \log_{6} \frac{1}{(2x)^4} \).
03

Separate the Expressions

The expression \( \frac{1}{(2x)^4} \) can be divided into two parts, 1 and \( (2x)^4 \). Thus, the logarithmic expression now becomes \( \log_{6} \frac{1}{16x^4} \).

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