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91Ó°ÊÓ

Find the domain, \(x\) -intercept, and vertical asymptote of the logarithmic function and sketch its graph. $$h(x)=\log _{4}(x-3)$$

Short Answer

Expert verified
The domain of \(h(x)\) is \(x>3\). The \(x\)-intercept is \(x = 4\). The vertical asymptote is \(x = 3\).

Step by step solution

01

Find the Domain

The domain of a log function \(h(x) = \log_b (x-a)\) is when \(x-a > 0\). So for the function \(h(x) = \log_4 (x-3)\), the domain would be \(x>3\). This is because log functions only take positive arguments.
02

Solve for the x intercept

Set \(h(x) = 0\) to solve for \(x\). We get \(0 = \log_4 (x-3)\). By definition of a logarithm, this implies that \(x-3 = 4^0\), since any number raised to the power of zero is 1. Therefore, \(x = 3+1 = 4\). Thus, the x-intercept is \(x = 4\).
03

Identify the Vertical Asymptote

For the function \(h(x) = \log_4 (x-3)\), the vertical asymptote is \(x = 3\). This is the boundary of the domain where the function tends to \(\pm \infty\).
04

Sketch the graph

Base the sketch on these findings. It should show the vertical asymptote at \(x = 3\), it should go through the x-intercept at \(x=4\), and the part of the graph should be to the right of \(x = 3\).

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