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Write the exponential equation in logarithmic form. For example, the logarithmic form of \(2^{3}=8\) is \(\log _{2} 8=3\). $$4^{-3}=\frac{1}{64}$$

Short Answer

Expert verified
The logarithmic form of the equation is \(\log_{4} \frac{1}{64}=-3\).

Step by step solution

01

Identify the base, exponent and result

In the given exponential equation \(4^{-3}=\frac{1}{64}\), the base is 4, the exponent is -3 and the result is \(\frac{1}{64}\).
02

Write the given equation in logarithmic form

Applying the logarithmic rule, the equation in logarithmic form will be \(\log_{b} x=y\). Plugging in values, we get \(\log_{4} \frac{1}{64}=-3\)

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