/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 75 The path of a diver is given by ... [FREE SOLUTION] | 91Ó°ÊÓ

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The path of a diver is given by \(y=-\frac{4}{9} x^{2}+\frac{24}{9} x+12\) where \(y\) is the height (in feet) and \(x\) is the horizontal distance from the end of the diving board (in feet). What is the maximum height of the diver?

Short Answer

Expert verified
The maximum height of the diver is 14 feet.

Step by step solution

01

Identify the coefficients

From the equation \(y=-\frac{4}{9}x^2 + \frac{24}{9}x + 12\), identify \(a\), \(b\), and \(c\). Here, \(a=-\frac{4}{9}\), \(b=\frac{24}{9}\), and \(c=12\).
02

Calculate the x-coordinate of the vertex

Apply the vertex formula \(x=-\frac{b}{2a}\) to find the x-coordinate of the vertex. Substituting the identified coefficients yields \(x=-\frac{\frac{24}{9}}{2*(-\frac{4}{9})}\), which simplifies to \(x=3\).
03

Calculate the y-coordinate of the vertex

Substitute \(x=3\) back into the equation to find the corresponding y-value (height). This gives \(y=-\frac{4}{9}*3^2 + \frac{24}{9}*3 + 12\), which simplifies to \(y=14\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertex of a Parabola
The vertex of a parabola is the highest or lowest point on the graph, depending on whether the parabola opens upwards or downwards, respectively. For the given quadratic function \( y=-\frac{4}{9}x^2 + \frac{24}{9}x + 12 \), since the coefficient of the \( x^2 \) term is negative, the parabola opens downwards, and thus the vertex represents the maximum point.
To find the vertex, we can use the formula \( x=-\frac{b}{2a} \) where \( a \) and \( b \) are the coefficients from the quadratic equation in the form \( y=ax^2+bx+c \). This formula gives us the x-coordinate of the vertex after substituting the identified coefficients. Following this method ensures a straightforward process to pinpoint the parabola’s peak or valley.
Once the x-coordinate is calculated, substituting this value back into the original equation gives us the y-coordinate, thus completing the vertex's coordinates \( (x, y) \), which in this exercise specifically yields \( (3, 14) \).
Maximum Height
In the context of projectile motion, such as a diver's path, the maximum height is the greatest y-value the object reaches. For quadratic functions like our example, this maximum height corresponds to the y-coordinate of the vertex when the parabola opens downwards.
Once the vertex is located using the aforementioned vertex formula, the y-value at this point is calculated by substituting the x-coordinate (in this case, 3 feet) back into the original function. The resulting y-value gives you the maximum height the diver reaches above the water surface, representing the apex of the dive. For the diver’s path defined by \( y=-\frac{4}{9}x^2 + \frac{24}{9}x + 12 \), the computation shows that the maximum height reached is 14 feet.
Factoring Quadratics
Factoring quadratics is a powerful tool for solving quadratic equations. It involves breaking down the quadratic into a product of binomials. However, in the case of our example \( y=-\frac{4}{9}x^2 + \frac{24}{9}x + 12 \), the coefficients are not ideal for simple factorization.
In some cases, if the quadratic is factorable over the integers, it can be expressed in the form \( y=(mx + n)(px + q) \), where \( m, n, p, \) and \( q \) are integers. Factoring is beneficial for finding the roots of the parabola—the x-values where the graph intersects the x-axis—but it is not necessary for finding the vertex or maximum height. Instead, as shown in the exercise, using the vertex formula and substituting the resulting x-coordinate of the vertex into the original equation proves to be an efficient method for these particular calculations.

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