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For (a) \(f(1)\), perform synthetic division where \(c = 1\). Simply plug 1 into the formula \(4(1)^4-16(1)^3+7(1)^2+20\). The remainder you get is the value of \(f(1)\). Repeat this step for \(f(-2)\), \(f(5)\), and \(f(-10)\). For (b) \(f(-2)\), perform synthetic division where \(c = -2\). Plug -2 into the formula \(4(-2)^4-16(-2)^3+7(-2)^2+20\). For (c) \(f(5)\), perform synthetic division where \(c = 5\). Plug 5 into the formula \(4(5)^4-16(5)^3+7(5)^2+20\).For (d) \(f(-10)\), perform synthetic division where \(c = -10\). Plug -10 into the formula \(4(-10)^4-16(-10)^3+7(-10)^2+20\).

After getting the results from Step 1, verify it using another way. Namely, substitute the value of \(c\) directly into the function and confirm it matches with what you got using synthetic division in Step 1.