/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 (a) state the domain of the func... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) state the domain of the function, (b) identify all intercepts, (c) find any vertical and horizontal asymptotes, and (d) plot additional solution points as needed to sketch the graph of the rational function. . \(P(x)=\frac{1-3 x}{1-x}\)

Short Answer

Expert verified
The domain of the function \(P(x) = \frac{1 - 3x}{1 - x}\) is all real numbers except \(x=1\). The x-intercept and y-intercept can be found by setting the numerator equal to zero and plugging in \(x=0\) into the function, respectively. The function has a vertical asymptote at \(x = 1\) and a horizontal asymptote at \(y = 3\). After identifying these features, the sketch of the graph can be completed.

Step by step solution

01

Domain of the Function

Firstly, find the domain of the given rational function. The domain of a rational function is all real numbers except the values that make the denominator equal to zero. So, solve \(1-x = 0\) to find the number that is not in the domain. Therefore, the domain of the function \(P(x) = \frac{1 - 3x}{1 - x}\) is all real numbers x except \(x = 1\).
02

Finding the Intercepts

Next, find the intercepts of the function. To find the x-intercept, set the numerator equal to zero and solve for x: \(1 - 3x =0\). To find the y-intercept, plug in \(x = 0\) into the function and solve for \(P(x)\). Therefore, the intercepts are based on the solution of these two equations.
03

Find the Vertical and Horizontal Asymptotes

To identify the vertical asymptote of the function, look for the values of x that make the denominator zero (but weren't excluded from the domain). Solving the equation \(1 - x = 0\), obtains the vertical asymptote \(x = 1\). For horizontal asymptote, compare the degrees of the numerator and the denominator. Since both are of degree 1 and the coefficient of x in the denominator is -1 while in the numerator is -3, the horizontal asymptote is \(y =\frac {-3}{-1} =3 \).
04

Plotting the Graph

After all these steps, now add the intercepts and asymptotes onto your graph. You could also plot additional points if needed. This would complete the sketch of your graph for the function \(P(x)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain of a Function
Understanding the domain of a function is an important starting point for analyzing any function, especially rational functions. The domain consists of all the possible values that can be input into the function without causing any mathematical errors or undefined behaviors.
For rational functions, these are usually any values that don't make the denominator zero. If the denominator is zero, the function is undefined at that point.
In our exercise with the function \(P(x) = \frac{1 - 3x}{1 - x}\):
  • Set the denominator \(1-x=0\) to find where the function is undefined.
  • Solve for \(x\) to get \(x=1\). This means \(x=1\) is excluded from the domain.
Therefore, the domain of the function \(P(x)\) is all real numbers except \(x=1\). Understanding the domain helps us know where to plot the function and where to expect potential discontinuities.
Intercepts
Intercepts are points where the graph of the function crosses the axes. These are important reference points for sketching and understanding the function's behavior.
  • **X-Intercept**: This is where the graph crosses the x-axis. To find it, set the numerator equal to zero because at the intercept, \(P(x) = 0\).
  • **Y-Intercept**: This is where the graph crosses the y-axis. To find it, substitute \(x = 0\) into the function \(P(x)\).
For the function \(P(x) = \frac{1 - 3x}{1 - x}\):- To find the x-intercept, solve \(1 - 3x = 0\), giving \(x = \frac{1}{3}\). This means the graph crosses the x-axis at \(x = \frac{1}{3}\).- For the y-intercept, substitute \(x = 0\) into the function, resulting in \(P(0) = \frac{1}{1} = 1\). This gives us the point \((0, 1)\).
Finding these intercepts makes it easier to sketch the graph, as they serve as key markers.
Asymptotes
Asymptotes are lines that the graph of a function approaches but never touches or crosses. They paint a clear picture of the function's behavior as it extends towards infinity or in the case of vertical asymptotes, at specific points.
  • **Vertical Asymptote**: Occurs where the function is undefined. For \(P(x) = \frac{1 - 3x}{1 - x}\), set the denominator \(1 - x = 0\).
  • **Horizontal Asymptote**: Determined by comparing the degrees of the numerator and denominator.
- For the vertical asymptote, solving \(1 - x = 0\) finds \(x = 1\).- For the horizontal asymptote, since both numerator and denominator are of degree 1, we look at the coefficients: \(\frac{-3}{-1} = 3\), so the horizontal asymptote is \(y=3\).
Including asymptotes in the graph helps define its boundaries and aids in understanding how the function behaves at extreme values.
Graphing Functions
Once we know the domain, intercepts, and asymptotes of a function, we can begin to sketch the graph.
Rational functions, like \(P(x) = \frac{1-3x}{1-x}\), often have complex shapes, so these identifiers become our guide.
  • **Plot Known Points**: Start by plotting any intercepts and marking the asymptotes.
  • **Evaluate Additional Points**: Choose some points within the domain to further refine the curve.
Steps to plot:1. Mark the vertical asymptote at \(x=1\), and the horizontal asymptote at \(y=3\).2. Place the x-intercept at \((\frac{1}{3}, 0)\) and the y-intercept at \((0, 1)\).3. To fill in the graph, calculate \(P(x)\) for other values of \(x\) to understand the curve's path.
Graphing becomes easier as it transforms abstract equations into visible shapes, making it clear where the function increases or decreases and its overall behavior.

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