/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 Use long division to divide. \... [FREE SOLUTION] | 91Ó°ÊÓ

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Use long division to divide. \(\frac{2 x^{3}-4 x^{2}-15 x+5}{(x-1)^{2}}\)

Short Answer

Expert verified
The result of the division is \(2x - 1 - 9 - \frac{15}{x^2 -2x + 1}\).

Step by step solution

01

Polynomial Long Division Setup

To set up the long division, we write \(2x^3 - 4x^2 - 15x + 5\) inside the division symbol and \((x-1)^2 = x^2 - 2x + 1\) outside, such as \(\frac{2x^3 - 4x^2 - 15x + 5}{x^2 - 2x + 1}\).
02

Divide

Now we divide \(2x^3\) by \(x^2\) to get \(2x\). We then multiply \(x^2 - 2x + 1\) by \(2x\) and write it beneath the relevant terms of \(2x^3 - 4x^2 - 15x\), then subtract this from those top terms. We should be careful about the signs here: the subtraction involves changing the signs of all terms. This results in an intermediate polynomial of \(-x^2 - 11x + 5\).
03

Continue Dividing

We repeat what we did in step 2. Divide the first term of the intermediate polynomial (-x^2) by the first term of the divisor (x^2) to get -1. Multiplying \(-1\) by the polynomial \('x^2 -2x + 1'\) gives us \('-x^2 + 2x -1'\). We write this beneath -x^2 - 11x + 5 and subtract, leading to \('-9x + 6'\).
04

Repeat Process

-9 divided by 1 gives -9, hence -9x is now our new divisor for the remaining term. Multiplicating and subtracting gives a leftover of -15.
05

Write Final Answer

The result of the division is then the sum of the terms found at each step, which in this case is \(2x - 1 - 9 - 15\). But since we can't go any further with the division, -15 must remain as the remainder of our division: \(2x - 1 -9 - \frac{15}{x^2 -2x + 1}\).

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