/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 88 Determine whether the function i... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine whether the function is even, odd, or neither. Then describe the symmetry. $$ f(x)=x \sqrt{1-x^{2}} $$

Short Answer

Expert verified
The function \(f(x) = x\sqrt{1-x^2}\) is odd and is symmetric about the origin.

Step by step solution

01

Test for Evenness

Substitute \(-x\) for \(x\) to check if \(f(x) = f(-x)\):\[f(-x) = -x\sqrt{1-(-x)^2} = -x\sqrt{1-x^2}\]Clearly, \(f(x) \neq f(-x)\) so the function is not even.
02

Test for Oddness

To find if it's odd, check if \(f(x) = -f(-x)\):\[ -f(-x) = x\sqrt{1-x^2}\]That matches the definition of \(f(x)\), therefore, the function is odd.
03

Describe Symmetry

Odd functions are symmetric about the origin. Therefore \(f(x) = x\sqrt{1-x^2}\) is symmetric about the origin.

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