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Find the center and radius of the circle, and sketch its graph. $$ \left(x-\frac{1}{2}\right)^{2}+\left(y-\frac{1}{2}\right)^{2}=\frac{9}{4} $$

Short Answer

Expert verified
The center of the circle is \((\frac{1}{2}, \frac{1}{2}\)), and the radius is \(\frac{3}{2}\).

Step by step solution

01

Identifying the center

The center of the circle is the point (a, b), which is obtained from the equations by equating coefficients: this gives us a = \(\frac{1}{2}\) and b = \(\frac{1}{2}\). Therefore, the center of the circle is \((\frac{1}{2}, \frac{1}{2})\).
02

Finding the radius

The radius of the circle is obtained by taking the square root of the constant term in the equation. In this case, the constant term is \(\frac{9}{4}\), therefore the radius r is equal to the square root of \(\frac{9}{4}\), which simplifies to give r = \(\frac{3}{2}\).
03

Graph the Circle

On a coordinate plane, plot the center at point \((\frac{1}{2}, \frac{1}{2})\). Then, using the radius of \(\frac{3}{2}\), draw a circle around the center point. Ensure that all points on the circumference of the circle are \(\frac{3}{2}\) units away from the center.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Center of the Circle
The center of a circle on a coordinate plane is a crucial aspect that determines the circle's position. It is usually denoted by the coordinates \((a, b)\). These coordinates are directly derived from the equation of the circle given in standard form: \((x-a)^2 + (y-b)^2 = r^2\). In the equation, \(a\) and \(b\) represent the center of the circle.
To identify the center from an equation such as \(\left(x-\frac{1}{2}\right)^{2}+\left(y-\frac{1}{2}\right)^{2}=\frac{9}{4}\), you can observe the values subtracted from \(x\) and \(y\) inside the parentheses.
The terms \(-\frac{1}{2}\) for \(x\) and \(-\frac{1}{2}\) for \(y\) indicate that the center of the circle is at \((\frac{1}{2}, \frac{1}{2})\).
This point, \((\frac{1}{2}, \frac{1}{2})\), acts as a fixed point around which the entire circle is evenly distributed on the coordinate plane.
Defining the Radius of the Circle
The radius of a circle is a measure of how large or small the circle is, extending from its center to any point on its circumference. Simply put, it is the distance from the center of the circle to its edge.
In a circle's equation \((x-a)^2 + (y-b)^2 = r^2\), the \(r^2\) term represents the square of the radius. So, to find the radius, you need to take the square root of this term.
For the equation \(\left(x-\frac{1}{2}\right)^{2}+\left(y-\frac{1}{2}\right)^{2}=\frac{9}{4}\), the square of the radius is \(\frac{9}{4}\).
  • Square root of \(\frac{9}{4}\) is \(\frac{3}{2}\).
This tells us that the radius is \(\frac{3}{2}\) units. It shows all points on the circle are \(\frac{3}{2}\) units away from the center.
Using the Coordinate Plane
The coordinate plane is an essential tool for graphing shapes and solving geometric problems. It consists of two axes, the horizontal \(x\)-axis and the vertical \(y\)-axis, meeting at the origin \((0,0)\), which divides the plane into four quadrants.
In our exercise, the coordinate plane helps locate the circle's center and outline its radius for accurate graphing.
  • Locate the center point \((\frac{1}{2}, \frac{1}{2})\) on the plane.
  • From this center, use the radius \(\frac{3}{2}\) to mark points that distance away in all directions.
This method ensures that when you draw the circle, it is symmetrical around the center and maintains uniform distance (the radius) in every direction. Understanding how to utilize the coordinate plane is fundamental in graphing and visualizing the properties of the circle.

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