/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 74 Write the standard form of the e... [FREE SOLUTION] | 91Ó°ÊÓ

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Write the standard form of the equation of the circle with the given characteristics. Center: (3,-2)\(;\) Solution point: (-1,1)

Short Answer

Expert verified
The standard form of the equation of the circle with center at (3,-2) and a point at (-1,1) is \((x-3)^2 + (y+2)^2 = 25\).

Step by step solution

01

Calculate the radius of the circle

To calculate the radius \(r\), we can use the distance formula with the coordinates of the center of the circle (h,k) as \((x_1 , y_1)\) and the given point on the circle (-1,1) as \((x_2, y_2)\). Therefore, the radius will be \(r =\sqrt{((-1 - 3)^2 + (1 + 2)^2)}\). Simplifying this, we get \(r = \sqrt{(-4)^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5\).
02

Write the equation of the circle in standard form

After calculating the radius as 5, we can substitute this radius and the center of the circle \((h,k) = (3,-2)\) into the standard form of the circle's equation \((x-h)^2 + (y-k)^2 = r^2\). This will give us our final equation for the circle as \((x-3)^2 + (y+2)^2 = 5^2\).

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