/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Graph the functions \(f, g,\) an... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Graph the functions \(f, g,\) and \(f+g\) on the same set of coordinate axes. $$ f(x)=x^{2}, \quad g(x)=-2 x $$

Short Answer

Expert verified
The graphs of \(f(x) = x^{2}\), \(g(x) = -2x\), and \(f+g(x) = x^{2} - 2x\) are a upward parabola, a descending line, and a shifted parabola respectively.

Step by step solution

01

Graphing function \(f(x) = x^{2}\)

Start by plotting the function \(f(x) = x^{2}\) on the coordinate axes. Since this is a quadratic function, it will be a parabola opening upwards, passing through the origin (0,0).
02

Graphing function \(g(x) = -2x\)

Next, plot the function \(g(x) = -2x\). This is a linear function with a negative slope, which means it will be a straight line through the origin and decreasing as x increases.
03

Calculating \(f+g(x)\)

Before graphing the sum of the functions, we need to calculate \(f+g(x)\). This is done by adding together the corresponding pair for every x, i.e., \((f+g)(x) = f(x) + g(x)= x^{2} + (-2x) = x^{2} - 2x\). This is another quadratic function.
04

Graphing function \(f+g(x)\)

Finally, plot the function \(f+g(x) = x^{2} - 2x\). The combined function will also be parabolic like \(f\), but shifted due to the linear component \(g\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Functions
Quadratic functions are a fundamental concept in algebra, characterized by an equation of the form \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants, and \( a \) is not equal to zero. The graph of a quadratic function is called a parabola.

When graphing a quadratic function such as \( f(x) = x^2 \), we start by determining the shape of the graph. Since the coefficient of \( x^2 \) is positive, the parabola opens upwards. Key points to identify include the vertex of the parabola, which for the function \( f(x) = x^2 \) is at the origin (0,0), and the axis of symmetry, which, in this case, is the y-axis.

The parabola will be symmetric about the axis of symmetry and the vertex is the lowest point on the graph for an upward-opening parabola. By plotting additional points on the graph such as (1,1) and (-1,1), we get a clearer picture of its symmetrical shape. Quadratic functions exhibit this symmetry and U-shape, which are hallmarks of their graphs.
Linear Functions
Linear functions are another cornerstone of algebraic graphing, generally represented by an equation of the form \( y = mx + b \), where \( m \) represents the slope and \( b \) is the y-intercept. These functions create straight lines when graphed on a coordinate plane.

For the linear function given in our exercise, \( g(x) = -2x \), the graph will be a straight line without a y-intercept term (\( b = 0 \)), meaning it crosses the origin. The slope \( m \) is negative, so the line will decrease, or go down and to the right, as \( x \) increases. This linear equation explains that for every one unit you move to the right along the x-axis, you move two units down along the y-axis.

To graph a linear equation like \( g(x) = -2x \), simply plot two points that satisfy the equation and draw a line through them. For example, using (0,0) and (1,-2) gives us enough information to extend the line across the graph. The simplicity and predictability of linear functions make them indispensable for understanding changes between variables.
Function Addition
Function addition involves creating a new function by adding two functions together. The new function, denoted \((f+g)(x)\), is formed by adding the values of \(f(x)\) and \(g(x)\) for any given \(x\).

In our exercise, we are asked to graph \((f+g)(x)\), where \(f(x) = x^2\) and \(g(x) = -2x\). To do this, we add the two functions together to get \((f+g)(x) = x^2 - 2x\). Like \( f(x) \), this combined function is also quadratic due to the \( x^2 \) term, but the \( -2x \) term will affect its shape and position on the graph.

Graphing \( (f+g)(x) = x^2 - 2x \) reveals a parabola shifted from the original \( f(x) \). It is essential to find the vertex of this new parabola, which can be done by completing the square or using the vertex formula \( (-b/(2a), f(-b/(2a))) \). Plotting points, like we did for \( f(x) \) and \( g(x) \), provides more accuracy for the graph. By understanding and practicing function addition, students can tackle more complex graphing problems that involve the merging of multiple function types.

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Most popular questions from this chapter

Write a sentence using the variation terminology of this section to describe the formula. Volume of a right circular cylinder: \(V=\pi r^{2} h\)

The total sales (in billions of dollars) for CocaCola Enterprises from 2000 through 2007 are listed below. (Source: Coca-Cola Enterprises, Inc.) $$\begin{array}{llll} 2000 & 14.750 & 2004 & 18.185 \\ 2001 & 15.700 & 2005 & 18.706 \\ 2002 & 16.899 & 2006 & 19.804 \\ 2003 & 17.330 & 2007 & 20.936 \end{array}$$ (a) Sketch a scatter plot of the data. Let \(y\) represent the total revenue (in billions of dollars) and let \(t=0\) represent 2000 . (b) Use a straightedge to sketch the best-fitting line through the points and find an equation of the line. (c) Use the regression feature of a graphing utility to find the least squares regression line that fits the data. (d) Compare the linear model you found in part (b) with the linear model given by the graphing utility in part (c). (e) Use the models from parts (b) and (c) to estimate the sales of Coca-Cola Enterprises in 2008 . (f) Use your school's library, the Internet, or some other reference source to analyze the accuracy of the estimate in part (e).

Use Hooke's Law for springs, which states that the distance a spring is stretched (or compressed) varies directly as the force on the spring. A force of 265 newtons stretches a spring 0.15 meter (see figure). (a) How far will a force of 90 newtons stretch the spring? (b) What force is required to stretch the spring 0.1 meter?

The lengths (in feet) of the winning men's discus throws in the Olympics from 1920 through 2008 are listed below. (Source: International Olympic Committee) $$\begin{array}{llllll} 1920 & 146.6 & 1956 & 184.9 & 1984 & 218.5 \\ 1924 & 151.3 & 1960 & 194.2 & 1988 & 225.8 \\ 1928 & 155.3 & 1964 & 200.1 & 1992 & 213.7 \\ 1932 & 162.3 & 1968 & 212.5 & 1996 & 227.7 \\ 1936 & 165.6 & 1972 & 211.3 & 2000 & 227.3 \\ 1948 & 173.2 & 1976 & 221.5 & 2004 & 229.3 \\ 1952 & 180.5 & 1980 & 218.7 & 2008 & 225.8 \end{array}$$ (a) Sketch a scatter plot of the data. Let \(y\) represent the length of the winning discus throw (in feet) and let \(t=20\) represent 1920 (b) Use a straightedge to sketch the best-fitting line through the points and find an equation of the line. (c) Use the regression feature of a graphing utility to find the least squares regression line that fits the data. (d) Compare the linear model you found in part (b) with the linear model given by the graphing utility in part (c). (e) Use the models from parts (b) and (c) to estimate the winning men's discus throw in the year 2012 .

The winning times (in minutes) in the women's 400-meter freestyle swimming event in the Olympics from 1948 through 2008 are given by the following ordered pairs. $$\begin{array}{lll} (1948,5.30) & (1972,4.32) & (1996,4.12) \\ (1952,5.20) & (1976,4.16) & (2000,4.10) \\ (1956,4.91) & (1980,4.15) & (2004,4.09) \\ (1960,4.84) & (1984,4.12) & (2008,4.05) \\ (1964,4.72) & (1988,4.06) & \\ (1968,4.53) & (1992,4.12) & \end{array}$$ A linear model that approximates the data is \(y=-0.020 t+5.00,\) where \(y\) represents the winning time (in minutes) and \(t=0\) represents \(1950 .\) Plot the actual data and the model on the same set of coordinate axes. How closely does the model represent the data? Does it appear that another type of model may be a better fit? Explain. (Source: International Olympic Committee)

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