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Chapter 1: Problem 22

Evaluate the indicated function for \(f(x)=x^{2}+1\) and \(g(x)=x-4\). $$ (f+g)(t-2) $$

Short Answer

Expert verified
The value of (f+g)(t-2) is \(t^2 - 3t - 1\).

Step by step solution

01

Addition of functions

The functions f(x) and g(x) given are \(f(x) = x^2+1\) and \(g(x) = x-4\). When you add these functions together you get a new function, \(h(x)\). Here, \(h(x) = f(x) + g(x) = (x^2+1) + (x-4) = x^2 + x - 3.
02

Substitute the value

In the original exercise, we are asked to find the value of (f+g)(t-2). So now we just substitute \(x = t-2\) into our new function \(h(x)\): \(h(t-2) = (t-2)^2 + (t-2) - 3 = t^2 - 4t + 4 + t - 2 - 3 = t^2 - 3t - 1.

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Most popular questions from this chapter

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