/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 93 Determine whether the statement ... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether the statement is true or false. Justify your answer.The Binomial Theorem could be used to produce each row of Pascal's Triangle.

Short Answer

Expert verified
The statement is True. Each row of Pascal's Triangle can indeed be produced using Binomial Theorem, as the coefficients in the binomial expansion correspond to the numbers in each row of Pascal's Triangle.

Step by step solution

01

Understanding the Concepts

The Binomial Theorem states that \( (a+b)^n = \sum_{k=0}^n {n \choose k} a^{n-k}b^k \), where \(n\) is a nonnegative integer and \( {n \choose k} \) are binomial coefficients. Pascal's triangle, on the other hand, is a triangular array consisting of the coefficients of binomial expansions.
02

Relating Both Concepts

We can see a connection between the Binomial Theorem and Pascal's Triangle. The coefficients in the expansion of \( (a+b)^n \) as defined by the Binomial Theorem correspond to the nth row of numbers in Pascal's Triangle.
03

Verifying the Statement

On expanding \( (a+b)^n \) using the Binomial Theorem, we see the coefficients regenerated correspond to the each row in Pascal's Triangle depending on the power \(n\). For instance, the expansion of \( (a+b)^2 \) gives \(a^2 + 2ab + b^2\), and the coefficients 1, 2 and 1 form the third row of Pascal's Triangle. Similarly, if we increase the power \(n\), the coefficients would correspond to the next rows in the Triangle directly indicating that the Binomial Theorem can be used to produce each row in Pascal's Triangle.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pascal's Triangle
Pascal's Triangle is a simple and powerful mathematical tool represented as a triangular array of numbers. It starts with a single 1 at the top. Each number in the triangle is the sum of the two numbers directly above it in the previous row. This pattern continues infinitely downwards, creating rows of numbers with fascinating properties.
To understand Pascal's Triangle, let's look at the first few rows:
  • Row 0: 1
  • Row 1: 1, 1
  • Row 2: 1, 2, 1
  • Row 3: 1, 3, 3, 1
  • Row 4: 1, 4, 6, 4, 1
Each number represents a binomial coefficient from the expansion of (a+b)^n, which we'll explore more in the other sections. Row n of Pascal's Triangle gives the coefficients from (a+b)^n.
Pascal's Triangle isn't just about generating numbers—it provides a delightful insight into patterns and relationships inherent in mathematics, including binomial expansions and probabilities.
binomial coefficients
Binomial coefficients are the core building blocks of binomial expansions. They are the numbers that appear in Pascal's Triangle. Binomial coefficients are represented using the formula \({n \choose k}\), pronounced as "n choose k."
This represents the number of ways to choose k elements from a set of n elements, which is fundamentally a combinatorial concept. The formula for a binomial coefficient is given by:
  • \({n \choose k} = \frac{n!}{k!(n-k)!}\)
where \(!\) is the factorial symbol representing the product of all positive integers up to that number.
In the context of the binomial theorem, the binomial coefficients dictate how each term in the expansion of \((a+b)^n\) is constructed. For example, when \((a+b)^2\) is expanded, the coefficients 1, 2, and 1 in the expression \(a^2 + 2ab + b^2\) correspond to row 2 of Pascal's Triangle.
binomial expansions
Binomial expansions refer to the process of expanding expressions raised to a power, specifically of the form \((a+b)^n\). The Binomial Theorem provides the formula for such expansions:
  • \((a+b)^n = \sum_{k=0}^n {n \choose k} a^{n-k} b^k\)
This formula is pivotal in algebra, allowing us to simplify and compute expressions where a binomial is raised to any nonnegative integer power. Each term of the expansion is made up of binomial coefficients, powers of \(a\), and powers of \(b\).
By using the Binomial Theorem, we can produce not only terms of the expansion but also discover the coefficients as they align with the numbers in Pascal's Triangle. This alignment showcases the intimate link between abstract algebra and combinatorial patterns. The theorem facilitates the calculation of any specific term in a binomial expansion, streamlining processes from simple cases like \((a+b)^2\) to more complex instances such as \((a+b)^{10}\).

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Most popular questions from this chapter

Complete the table and describe the result.$$\begin{array}{|c|c|c|c|} \hline n & r & _{n} C_{r} & _{n} C_{n-r} \\\\\hline 9 & 5 & & \\\\\hline 7 & 1 & & \\\\\hline 12 & 4 & & \\ \hline 6 & 0 & & \\\\\hline 10 & 7 & & \\\\\hline\end{array}$$,What characteristic of Pascal's Triangle does this table illustrate?

Use the following definition of the arithmetic mean \(\bar{x}\) of a set of \(n\) measurements \(x_{1}, x_{2}, x_{3}, \ldots, x_{n}\) \(\bar{x}=\frac{1}{n} \sum_{i=1}^{n} x_{i}\) Find the arithmetic mean of the six checking account balances 327.15 dollar ,785.69 dollar, 433.04 dollar, 265.38 dollar, 604.12 dollar and 590.30 dollar. Use the statistical capabilities of a graphing utility to verify your result.

The table shows the average prices \(f(t)\) (in cents per kilowatt hour) of residential electricity in the United States from 2003 through 2010 . (Source: U.S. Energy Information Administration ).$$\begin{array}{|c|c|}\hline \text { Year } & \text { Abcrage Poids }(10) \\\\\hline 2003 & 8.72 \\\2004 & 8.95 \\\2005 & 9.45 \\\2006 & 10.40 \\\2007 & 10.65 \\\2008 & 11.26 \\\2009 & 11.51 \\\2010 & 11.58 \\\\\hline\end{array}$$.(a) Use the regression feature of a graphing utility to find a cubic model for the data. Let \(t\) represent the year, with \(t=3\) corresponding to 2003 (b) Use the graphing utility to plot the data and the model in the same viewing window. (c) You want to adjust the model so that \(t=3\) corresponds to 2008 rather than \(2003 .\) To do this, you shift the graph of \(f\) five units to the left to obtain \(g(t)=f(t+5) .\) Use binomial coefficients to write \(g(t)\) in standard form. (d) Use the graphing utility to graph \(g\) in the same viewing window as \(f\) (e) Use both models to predict the average price in \(2011 .\) Do you obtain the same answer? (f) Do your answers to part (e) seem reasonable? Explain. (g) What factors do you think may have contributed to the change in the average price?

Which two functions have identical graphs, and why? Use a graphing utility to graph the functions in the given order and in the same viewing window. Compare the graphs. (a) \(f(x)=(1-x)^{3}\) (b) \(g(x)=1-x^{3}\) (c) \(h(x)=1+3 x+3 x^{2}+x^{3}\) (d) \(k(x)=1-3 x+3 x^{2}-x^{3}\) (e) \(p(x)=1+3 x-3 x^{2}+x^{3}\)

Consider \(n\) independent trials of an experiment in which each trial has two possible outcomes: "success" or "failure." The probability of a success on each trial is \(p,\) and the probability of a failure is \(q=1-p .\) In this context, the term \(_{n} C_{k} p^{k} q^{n-k}\) in the expansion of \((p+q)^{n}\) gives the probability of \(k\) successes in the \(n\) trials of the experiment.To find the probability that the sales representative in Exercise 87 makes four sales when the probability of a sale with any one customer is \(\frac{1}{2},\) evaluate the term $$_{8} C_{4}\left(\frac{1}{2}\right)^{4}\left(\frac{1}{2}\right)^{4}$$, in the expansion of \(\left(\frac{1}{2}+\frac{1}{2}\right)^{8}\).

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