/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 62 Find the partial sum. $$\sum_{... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the partial sum. $$\sum_{n=51}^{100} n-\sum_{n=1}^{50} n$$

Short Answer

Expert verified
The partial sum of the given series is 2500.

Step by step solution

01

Summation of the series for the first sum

Firstly, we need to find the sum of the sequence from 51 to 100. Here, \[n=100-51+1=50\], \(a=51\) is the first term, and \(l=100\) is the last term of the series. The formula for the sum of an arithmetic series, \(\frac{n}{2}(a+l)\), gives us \(\frac{50}{2}(51+100)=3775.\)
02

Summation of the series for the second sum

The sum of the sequence from 1 to 50 is now calculated. Here, \[n=50-1+1=50\], \(a=1\) is the first term, and \(l=50\) is the last term of the series. Using the sum of an arithmetic series formula, \(\frac{n}{2}(a+l)\), gives us \(\frac{50}{2}(1+50)=1275.\)
03

Subtract the second sum from the first sum.

The last step is to subtract the two sums. The result is \[3775 - 1275 = 2500.\] Thus, \(\sum_{n=51}^{100} n-\sum_{n=1}^{50} n = 2500\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arithmetic Series
An arithmetic series is essentially the summation of all terms in an arithmetic sequence. In this type of sequence, each term is obtained by adding a constant value to the previous term. This constant is known as the common difference. For example, in the sequence 2, 5, 8, 11..., the common difference is 3.

An arithmetic series can be defined as the sum of terms of an arithmetic sequence. For example, if we take the sequence 1, 2, 3, 4, 5..., the arithmetic series is simply 1 + 2 + 3 + 4 + 5... Arithmetic series are widely used in calculations because they follow a simple pattern, making it easier to figure out the sum when lots of numbers are involved.

Recognizing an arithmetic sequence and finding its series help significantly in both small calculations and large numerical computations. It simplifies things, especially when you're tasked with finding partial sums like in our exercise.
Summation Formula
The summation formula for an arithmetic series is a straightforward and effective tool used to find the sum of a given arithmetic sequence. Instead of adding each number one by one, you can use this formula:
  • \[ S_n = \frac{n}{2} (a + l) \]
  • Where:
    • \( S_n \) is the sum of the series,
    • \( n \) is the number of terms,
    • \( a \) is the first term, and
    • \( l \) is the last term.
This formula allows you to bypass tedious calculations and jump straight to the answer. In the context of our problem, we needed to find the sum of sequences from 51 to 100 and from 1 to 50. Using the formula, we could quickly determine the partial sums, saving both time and possible errors in manual addition. This is why knowing and applying the summation formula is such a valuable skill in math.
Sequence
A sequence in mathematics is a set of numbers arranged in a specific order according to a certain rule. Think of it as a list where numbers follow a logical pattern. There are different kinds of sequences, and one common type is the arithmetic sequence.

In an arithmetic sequence, the difference between consecutive terms is always the same. It's like taking small, regular steps when you walk. For instance, in the sequence 3, 6, 9, 12..., each number increases by 3.

Understanding sequences is crucial because it forms the foundation for more complex concepts like arithmetic series and finding partial sums. Without understanding the predictable nature of sequences, tasks involving large numbers and their sums can become quite challenging. For students, grasping the idea of sequences is a key step toward mastering arithmetic series and other algebraic topics.

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Most popular questions from this chapter

Determine whether the statement is true or false. Justify your answer.A binomial that represents a difference cannot always be accurately expanded using the Binomial Theorem.

The table shows the average prices \(f(t)\) (in cents per kilowatt hour) of residential electricity in the United States from 2003 through 2010 . (Source: U.S. Energy Information Administration ).$$\begin{array}{|c|c|}\hline \text { Year } & \text { Abcrage Poids }(10) \\\\\hline 2003 & 8.72 \\\2004 & 8.95 \\\2005 & 9.45 \\\2006 & 10.40 \\\2007 & 10.65 \\\2008 & 11.26 \\\2009 & 11.51 \\\2010 & 11.58 \\\\\hline\end{array}$$.(a) Use the regression feature of a graphing utility to find a cubic model for the data. Let \(t\) represent the year, with \(t=3\) corresponding to 2003 (b) Use the graphing utility to plot the data and the model in the same viewing window. (c) You want to adjust the model so that \(t=3\) corresponds to 2008 rather than \(2003 .\) To do this, you shift the graph of \(f\) five units to the left to obtain \(g(t)=f(t+5) .\) Use binomial coefficients to write \(g(t)\) in standard form. (d) Use the graphing utility to graph \(g\) in the same viewing window as \(f\) (e) Use both models to predict the average price in \(2011 .\) Do you obtain the same answer? (f) Do your answers to part (e) seem reasonable? Explain. (g) What factors do you think may have contributed to the change in the average price?

Prove the identity. $$_{n} C_{r}=\frac{_{n} P_{r}}{r !}$$

\(A 3 \times 3 \times 3\) cube is made up of 27 unit cubes (a unit cube has a length, width, and height of 1 unit), and only the faces of each cube that are visible are painted blue, as shown in the figure. (a) Complete the table to determine how many unit cubes of the \(3 \times 3 \times 3\) cube have 0 blue faces, 1 blue face, 2 blue faces, and 3 blue faces. $$\begin{array}{|l|l|l|l|l|} \hline \begin{array}{l} \text { Number of } \\ \text { Blue Cube Faces } \end{array} & 0 & 1 & 2 & 3 \\ \hline 3 \times 3 \times 3 & & & & \\ \hline \end{array}$$ (b) Repeat part (a) for a \(4 \times 4 \times 4\) cube, a \(5 \times 5 \times 5\) cube, and a \(6 \times 6 \times 6\) cube. (c) What type of pattern do you observe? (d) Write formulas you could use to repeat part (a) for an \(n \times n \times n\) cube.

Use the Binomial Theorem to expand the complex number. Simplify your result. $$(1+i)^{4}$$

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