/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Find the indicated term of the g... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the indicated term of the geometric sequence. $$7 \text { th term: } \frac{8}{5},-\frac{16}{25}, \frac{32}{125},-\frac{64}{625}, \ldots$$

Short Answer

Expert verified
The 7th term of the geometric sequence is \(-\frac{8192}{15625}\).

Step by step solution

01

Identify the common ratio \(r\)

In this sequence, to get from one term to the next, we multiply by \(-\frac{2}{5}\), therefore \(r = -\frac{2}{5}\).
02

Identify the first term, \(a_1\)

The first term of the sequence is \(\frac{8}{5}\), thus \(a_1 = \frac{8}{5}\).
03

Apply the geometric sequence formula

To find the 7th term, plug the values into the formula. Therefore, \(a_7 = a_1 \times r^{(7-1)} = \frac{8}{5} \times (-\frac{2}{5})^{(7-1)} = \frac{8}{5} \times (-\frac{2}{5})^6\).
04

Calculate the 7th term

Compute the expression: \(a_7 = \frac{8}{5} \times (-\frac{2}{5})^6 = \frac{8}{5} \times \frac{64}{15625} = -\frac{8192}{15625}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Common Ratio
In a geometric sequence, each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio (denoted as r). This ratio is the engine that generates the sequence and determines its growth or decay. To identify the common ratio, simply divide any term by its preceding term.

For the given sequence \frac{8}{5},-\frac{16}{25}, \frac{32}{125},-\frac{64}{625},\text{...} the ratio between successive terms is consistent. Calculating r can be done by taking any term and dividing it by the term before it. In our case:
\( r = \frac{-\frac{16}{25}}{\frac{8}{5}} = -\frac{2}{5} \).

It's important to note that the common ratio can be positive or negative, which affects the sequence's behavior—alternating signs in terms, for example, are indicative of a negative common ratio.
Geometric Sequence Formula
With the common ratio in hand, one can calculate any term in a geometric sequence using the geometric sequence formula:
\( a_n = a_1 \times r^{(n-1)} \) where a_n is the nth term, a_1 is the first term, and r is the common ratio. The exponent (n-1) reflects how many times you multiply the first term by the common ratio to reach the nth term.

Understanding this formula allows you to efficiently find any term within a geometric sequence without having to calculate all the preceding terms. This is particularly useful for sequences with a large number of terms or when the specific term required is far from the initial term. For sequences that reduce or increase rapidly, this formula is an essential tool for pinpointing specific values.
Sequence Term Identification
Identifying a specific term within a geometric sequence involves a few clear steps. First, recognize the sequence pattern and establish the first term, a_1. Next, find the common ratio, r. Once you have these, use the geometric sequence formula as shown in the problem solution.

For example, to find the 7th term of our given geometric sequence, we insert our known values into the formula:
\( a_7 = a_1 \times r^{(7-1)} = \frac{8}{5} \times (-\frac{2}{5})^{(7-1)} = \frac{8}{5} \times (-\frac{2}{5})^6 \),
resulting in a_7 being \frac{8192}{15625}. This careful application of the geometric sequence formula simplifies the process of term identification and allows for rapid calculation of terms far along in the sequence.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the Binomial Theorem to expand the complex number. Simplify your result. $$(2-i)^{5}$$

Write all combinations of two letters that you can form from the letters \(A, B, C, D\) \(\mathrm{E}_{1}\) and \(\mathrm{F}\). (The order of the two letters is not important.)

A local college is forming a six-member research committee having one administrator, three faculty members, and two students There are seven administrators, 12 faculty members and 20 students in contention for the committee. How many six-member committees are possible?

The numbers \(a_{n}\) (in thousands) of AIDS cases reported from 2003 through 2010 can be approximated by \(a_{n}=-0.0126 n^{3}+0.391 n^{2}-4.21 n+48.5\) \(n=3,4, \ldots, 10\) where \(n\) is the year, with \(n=3\) corresponding to \(2003 .\) (Source: U.S. Centers for Disease Control and Prevention (a) Write the terms of this finite sequence. Use a graphing utility to construct a bar graph that represents the sequence. (b) What does the graph in part (a) say about reported cases of AIDS?

Consider \(n\) independent trials of an experiment in which each trial has two possible outcomes: "success" or "failure." The probability of a success on each trial is \(p,\) and the probability of a failure is \(q=1-p .\) In this context, the term \(_{n} C_{k} p^{k} q^{n-k}\) in the expansion of \((p+q)^{n}\) gives the probability of \(k\) successes in the \(n\) trials of the experiment.The probability of a sales representative making a sale with any one customer is \(\frac{1}{3} .\) The sales representative makes eight contacts a day. To find the probability of making four sales, evaluate the term $$_{8} C_{4}\left(\frac{1}{3}\right)^{4}\left(\frac{2}{3}\right)^{4}$$, in the expansion of \(\left(\frac{1}{3}+\frac{2}{3}\right)^{8}\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.