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Use the Binomial Theorem to expand and simplify the expression. $$(x+2 y)^{4}$$

Short Answer

Expert verified
The expanded and simplified form of \( (x + 2y)^4 \) using Binomial Theorem is \( x^4 + 8x^3y + 24x^2y^2 + 32xy^3 + 16y^4 \)

Step by step solution

01

Understand the Binomial Theorem

To apply the Binomial Theorem, we need to understand its formula. The Binomial Theorem starts with the index 'n' and decreases one at a time until it gets to zero. The formula for a binomial expansion is given by: \[ (a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^{k} \] where 'n' is the power on the binomial, 'a' and 'b' are the terms in the binomial, 'k' is the term number and \(\binom{n}{k}\) are the binomial coefficients calculated as \(\frac{n!}{k!(n-k)!}\).
02

Apply the Binomial Theorem

Now we apply the binomial theorem to the expression \( (x + 2y)^4 \). By substituting 'a' with 'x', 'b' with '2y' and 'n' with '4' in the binomial formula we get: \[ (x + 2y)^4 = \binom{4}{0} x^{4} (2y)^{0} + \binom{4}{1} x^{3} (2y)^{1} + \binom{4}{2} x^{2} (2y)^{2} + \binom{4}{3} x^{1} (2y)^{3} + \binom{4}{4} x^{0} (2y)^{4} \]
03

Calculate and simplify the expression

Now calculate the binomial coefficients and power values for each term. This will simplify the expression: \[ (x + 2y)^4 = 1*x^4*1 + 4*x^3*2y + 6*x^2*(2y)^2 + 4*x*(2y)^3 + 1*(2y)^4 \] \[ (x + 2y)^4 = x^4 + 8x^3y + 24x^2y^2 + 32xy^3 + 16y^4 \] So, the expanded form of \( (x + 2y)^4 \) is \( x^4 + 8x^3y + 24x^2y^2 + 32xy^3 + 16y^4 \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Expansion
The binomial expansion involves expanding expressions that are raised to a power using the Binomial Theorem. This theorem allows us to express the power of a sum, such as \((x + 2y)^4\), as a sum of terms involving binomial coefficients and powers of the individual terms. By using this approach, we can break down problems into simpler components, making calculations easier.

In our example, we observe the expression \((x + 2y)^4\). The application of the binomial theorem leads to a sequence of terms consisting of various powers of \(x\) and \(2y\). This involves calculating each term by applying the formula:
\[ \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^{k} \]
Each term follows the pattern of the binomial coefficients, alongside progressively increasing powers of \(b\) (in our case, \(2y\)), and decreasing powers of \(a\) (\(x\)). This method not only simplifies each step but ensures all possible combinations of terms are accounted for.
Binomial Coefficients
Binomial coefficients are crucial for binomial expansions and are denoted as \(\binom{n}{k}\). These coefficients can be thought of as the "weights" of each term in the binomial expansion. The coefficients are calculated using the formula:

\[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]

Where \(n!\) (n factorial) symbolizes the product of all positive integers up to \(n\), \(k!\) is the factorial of \(k\), and \((n-k)!\) is the factorial of \((n-k)\).

In our example, expanding \((x + 2y)^4\), we encountered coefficients: 1, 4, 6, 4, and 1. These values arise directly from the formula and help determine the contribution of each component of the expanded expression:
  • \(\binom{4}{0} = 1\)
  • \(\binom{4}{1} = 4\)
  • \(\binom{4}{2} = 6\)
  • \(\binom{4}{3} = 4\)
  • \(\binom{4}{4} = 1\)
Without these coefficients, the binomial expansion would lack structure and mathematical precision.
Polynomial Expansion
Polynomial expansion refers to representing an expression consisting of powers and terms, like our binomial, into a longer polynomial form. In the case of \((x + 2y)^4\), the polynomial expansion allows us to express the original binomial in a sum that contains each possible combination of the variables \(x\) and \(y\).

By expanding \((x + 2y)^4\), we obtain the polynomial:
\[x^4 + 8x^3y + 24x^2y^2 + 32xy^3 + 16y^4\]

This expanded form displays each term with its specific binomial coefficient. Each term shows an increasing power of \(y\), balanced by a corresponding decrease in the power of \(x\).

Understanding polynomial expansion is key to simplifying expressions, solving equations, and understanding graphical representations in algebra. It provides a foundation for more complex algebraic operations, such as finding roots or factoring polynomials.

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Most popular questions from this chapter

American roulette is a game in which a wheel turns on a spindle and is divided into 38 pockets. Thirty-six of the pockets are numbered \(1-36,\) of which half are red and half are black. Two of the pockets are green and are numbered 0 and 00 (see figure). The dealer spins the wheel and a small ball in opposite directions. As the ball slows to a stop, it has an equal probability of landing in any of the numbered pockets. (a) Find the probability of landing in the number 00 pocket. (b) Find the probability of landing in a red pocket. (c) Find the probability of landing in a green pocket or a black pocket. (d) Find the probability of landing in the number 14 pocket on two consecutive spins. (e) Find the probability of landing in a red pocket on three consecutive spins.

In the Louisiana Lotto game, a player randomly chooses six distinct numbers from 1 to \(40 .\) In how many ways can a player select the six numbers?

A fire company keeps two rescue vehicles. Because of the demand on the vehicles and the chance of mechanical failure, the probability that a specific vehicle is available when needed is \(90 \% .\) The availability of one vehicle is independent of the availability of the other. Find the probability that (a) both vehicles are available at a given time, (b) neither vehicle is available at a given time, and (c) at least one vehicle is available at a given time.

Three points that are not collinear determine three lines. How many lines are determined by nine points, no three of which are collinear?

A local college is forming a six-member research committee having one administrator, three faculty members, and two students There are seven administrators, 12 faculty members and 20 students in contention for the committee. How many six-member committees are possible?

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