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Use the following definition of the arithmetic mean \(\bar{x}\) of a set of \(n\) measurements \(x_{1}, x_{2}, x_{3}, \ldots, x_{n}\) \(\bar{x}=\frac{1}{n} \sum_{i=1}^{n} x_{i}\) $$\text { Prove that } \sum_{i=1}^{n}\left(x_{i}-\bar{x}\right)=0$$

Short Answer

Expert verified
The proof shows that the sum of the differences between each measurement and the mean of the measurements equals zero.

Step by step solution

01

Definition of Arithmetic Mean

Let's start with the definition of the arithmetic mean. Given a set of \(n\) measurements \(x_{1}, x_{2}, x_{3}, \ldots, x_{n}\), the arithmetic mean \(\bar{x}\) is defined as: \(\bar{x}=\frac{1}{n} \sum_{i=1}^{n} x_{i}\).
02

Substitution

Substitute the expression for \(\bar{x}\) in \(\sum_{i=1}^{n}\left(x_{i}-\bar{x}\right)\). This gives the equation: \(\sum_{i=1}^{n}\left(x_{i}-\frac{1}{n} \sum_{j=1}^{n} x_{j}\right)\).
03

Simplification

Let's distribute the summation over the subtraction, this gives us two separate sums: \(\sum_{i=1}^{n} x_{i} - \sum_{i=1}^{n} \frac{1}{n}\sum_{j=1}^{n} x_{j}\)The term on the right simplifies to:\(\frac{1}{n}\sum_{i=1}^{n}\sum_{j=1}^{n} x_{j} = \frac{1}{n}(n\sum_{i=1}^{n} x_{i}) = \sum_{i=1}^{n} x_{i}\)Therefore, \(\sum_{i=1}^{n} x_{i} - \sum_{j=1}^{n} x_{j} = 0\). Thus, proving that \(\sum_{i=1}^{n}\left(x_{i}-\bar{x}\right)=0\).
04

Conclusion

This proof shows that the sum of the differences between each measurement and the mean of the measurements is zero. It's a useful property that shows how, on average, the measurements deviate from the mean.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arithmetic Mean
The arithmetic mean, often simply called the 'average', is a fundamental concept in statistics and mathematics. It represents the central value of a set of numbers and is calculated by summing up all the measurements and dividing by the total count of measurements. In mathematical terms, if you have a set of measurements \(x_{1}, x_{2}, x_{3}, ..., x_{n}\), their arithmetic mean \(\bar{x}\) is given by \(\bar{x} = \frac{1}{n} \sum_{i=1}^{n} x_{i}\).
Using the definition of arithmetic mean can simplify complex data sets to a single value, making it easier to compare and analyze different data sets. While it is a helpful measurement, one should also be aware of its limitations: the arithmetic mean can be heavily influenced by outliers – extreme values that are significantly higher or lower than the rest of the data.
Mathematical Proof
A mathematical proof is a logical argument that establishes the truth of a statement beyond any doubt. It is the cornerstone of mathematics, ensuring that the results and principles we rely on are valid and reliable. In the context of our problem, proving that the sum of the differences between each measurement and the mean is zero \(\sum_{i=1}^{n}\left(x_{i}-\bar{x}\right) = 0\) provides a deep insight into how the arithmetic mean is related to the individual data points in a set.
Proofs often start with known facts or definitions, as happened here with the definition of arithmetic mean, followed by a sequence of justified steps that lead to the desired conclusion. Each step in a proof must be clear and follow logically from the previous steps or from accepted truths. The purpose of a proof is to demonstrate that no other conclusion can be drawn from the given premises.
Summation Notation
Summation notation, or sigma notation, is a concise way of representing the sum of a sequence of numbers. The Greek letter sigma \(\Sigma\) is used to signify summation. The general form of summation notation is \(\sum_{i=m}^{n} a_{i}\), which means the sum of \(a_{i}\) as \(i\) goes from a starting index \(m\) to an ending index \(n\).
In the context of our problem, we see the notation used twice: once to define the arithmetic mean and again to express summation across the set of measurements from which the mean was calculated. Understanding summation notation is crucial for manipulating series, especially when dealing with large data sets or complicated summation expressions, as it provides a standardized method to work with sums in a precise and efficient manner.
Averages in Statistics
Averages are essential tools in statistics, used to condense a large set of numbers into a single value representing the central tendency of the data. The arithmetic mean is the most widely recognized type of average, but it's not the only one. Other forms of averages include the median - the middle value when all measurements are sorted, and the mode - the most frequently occurring value.
The arithmetic mean is especially useful because it takes every value into account, which is suitable for normally distributed data without many outliers. However, statisticians must choose the appropriate type of average depending on the nature of the data they are analyzing. For example, in a skewed distribution with outliers, the median may be a better representation of the central tendency than the mean. Understanding various averages allows statisticians to interpret and analyze data sets effectively.

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Most popular questions from this chapter

The table shows the average prices \(f(t)\) (in cents per kilowatt hour) of residential electricity in the United States from 2003 through 2010 . (Source: U.S. Energy Information Administration ).$$\begin{array}{|c|c|}\hline \text { Year } & \text { Abcrage Poids }(10) \\\\\hline 2003 & 8.72 \\\2004 & 8.95 \\\2005 & 9.45 \\\2006 & 10.40 \\\2007 & 10.65 \\\2008 & 11.26 \\\2009 & 11.51 \\\2010 & 11.58 \\\\\hline\end{array}$$.(a) Use the regression feature of a graphing utility to find a cubic model for the data. Let \(t\) represent the year, with \(t=3\) corresponding to 2003 (b) Use the graphing utility to plot the data and the model in the same viewing window. (c) You want to adjust the model so that \(t=3\) corresponds to 2008 rather than \(2003 .\) To do this, you shift the graph of \(f\) five units to the left to obtain \(g(t)=f(t+5) .\) Use binomial coefficients to write \(g(t)\) in standard form. (d) Use the graphing utility to graph \(g\) in the same viewing window as \(f\) (e) Use both models to predict the average price in \(2011 .\) Do you obtain the same answer? (f) Do your answers to part (e) seem reasonable? Explain. (g) What factors do you think may have contributed to the change in the average price?

Use the Binomial Theorem to expand the complex number. Simplify your result. $$(1+i)^{4}$$

Solve for \(n\) $$14 \cdot_{n} P_{3}=_{n+2} P_{4}$$

The expansions of \((x+y)^{4},(x+y)^{5},\) and \((x+y)^{6}\) are as follows.$$\begin{aligned} (x+y)^{4}=& 1 x^{4}+4 x^{3} y+6 x^{2} y^{2}+4 x y^{3}+1 y^{4} \\\\(x+y)^{5}=& 1 x^{5}+5 x^{4} y+10 x^{3} y^{2}+10 x^{2} y^{3} \\\\(x+y)^{6}=& 1 x^{6}+6 x^{5} y+15 x^{4}+1 y^{5} \\\& \quad+6 x y^{5}+1 y^{6}\end{aligned}$$,(a) Explain how the exponent of a binomial is related to the number of terms in its expansion. (b) How many terms are in the expansion of \((x+y)^{n} ?\)

Use the following definition of the arithmetic mean \(\bar{x}\) of a set of \(n\) measurements \(x_{1}, x_{2}, x_{3}, \ldots, x_{n}\) \(\bar{x}=\frac{1}{n} \sum_{i=1}^{n} x_{i}\) $$\text { Prove that } \sum_{i=1}^{n}\left(x_{i}-\bar{x}\right)^{2}=\sum_{i=1}^{n} x_{i}^{2}-\frac{1}{n}\left(\sum_{i=1}^{n} x_{i}\right)^{2}$$

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